题目内容
| x-1 |
| x2-2x+1 |
| 1 |
| x2-1 |
| 2 |
| 2 |
| 2 |
分析:先将除法化为乘法,再将分子、分母因式分解,约分即可.
解答:解:原式=
•(x-1)(x+1)
=x+1;
当x=
-1时,原式=
-1+1=
.
故答案为
.
| x-1 |
| (x-1)2 |
=x+1;
当x=
| 2 |
| 2 |
| 2 |
故答案为
| 2 |
点评:本题考查了分式的化简求值,熟悉因式分解是解题的关键.
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题目内容
| x-1 |
| x2-2x+1 |
| 1 |
| x2-1 |
| 2 |
| 2 |
| 2 |
| x-1 |
| (x-1)2 |
| 2 |
| 2 |
| 2 |
| 2 |