题目内容
已知A=-
,B=-
,C=-
,则有( )
| 1998•1999 |
| 2000•2001 |
| 1998•2000 |
| 1999•2001 |
| 1998•2001 |
| 1999•2000 |
| A.A>B>C | B.C>B>A | C.B>A>C | D.B>C>A |
设A=
,B=
,C=
,
则A=
,B=
,C=
,
再由n2+5n+6>n2+4n+3>n2+3n+2;n2+n<n2+2n<n2+3n
可得:-C>-B>-A,
则C<B<A
故选A.
| n(n+1) |
| (n+2)(n+3) |
| n(n+2) |
| (n+1)(n+3) |
| n(n+3) |
| (n+1)(n+2) |
则A=
| n2+n |
| n2+5n+6 |
| n2+2n |
| n2+4n+3 |
| n2+3n |
| n2+3n+2 |
再由n2+5n+6>n2+4n+3>n2+3n+2;n2+n<n2+2n<n2+3n
可得:-C>-B>-A,
则C<B<A
故选A.
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已知a=-
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,c=-
,则abc=( )
| 1999×1999-1999 |
| 1998×1998+1998 |
| 2000×2000-2000 |
| 1999×1999+1999 |
| 2001×2001-2001 |
| 2000×2000+2000 |
| A、-1 | B、3 | C、-3 | D、1 |
已知A=-
,B=-
,C=-
,则有( )
| 1998•1999 |
| 2000•2001 |
| 1998•2000 |
| 1999•2001 |
| 1998•2001 |
| 1999•2000 |
| A、A>B>C |
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