题目内容
(1)(8a-7b)-(4a-5b)
(2)3(5x+4)-(3x-5)
(3)(6a-8b)-(4a-5b)
(4)(
a3-
a+
)-(
a3-
a2-
)
(5)-5x+(5x-8x)-(-12x+4x)+6x.
(2)3(5x+4)-(3x-5)
(3)(6a-8b)-(4a-5b)
(4)(
| 3 |
| 2 |
| 3 |
| 4 |
| 5 |
| 6 |
| 8 |
| 15 |
| 1 |
| 10 |
| 2 |
| 9 |
(5)-5x+(5x-8x)-(-12x+4x)+6x.
分析:先去括号,然后合并同类项求解.
解答:解:(1)原式=8a-7b-4a+5b=4a-2b;
(2)原式=15x+12-3x+5=12x+17;
(3)原式=6a-8b-4a+5b=2a-3b;
(4)原式=
a3-
a+
-
a3+
a2+
=
a3+
a2-
a+
;
(5)原式=-5x+5x-8x+12x-4x+6x=6x.
(2)原式=15x+12-3x+5=12x+17;
(3)原式=6a-8b-4a+5b=2a-3b;
(4)原式=
| 3 |
| 2 |
| 3 |
| 4 |
| 5 |
| 6 |
| 8 |
| 15 |
| 1 |
| 10 |
| 2 |
| 9 |
=
| 29 |
| 30 |
| 1 |
| 10 |
| 3 |
| 4 |
| 19 |
| 18 |
(5)原式=-5x+5x-8x+12x-4x+6x=6x.
点评:本题考查了整式的加减,解答本题的关键是掌握去括号法则以及合并同类项法则.
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