题目内容
计算:(1)
| x2 |
| y-x |
| y2 |
| y-x |
(2)
| a+1 |
| a-1 |
| a2+a |
| a2-1 |
分析:(1)同分母直接相加减,然后进行约分,(2)解决本题首先应通分,最后要注意将结果化为最简分式.
解答:解:(1)原式=
(1分)
=
(2分)
=
(3分)
=-x-y;(4分)
(2)解:原式=
-
(1分)
=
-
(2分)
=
(3分)
=
.(4分)
| x2-y2 |
| y-x |
=
| (x-y)(x+y) |
| y-x |
=
| (x-y)(x+y) |
| -(x-y) |
=-x-y;(4分)
(2)解:原式=
| a+1 |
| a-1 |
| a(a+1) |
| (a+1)(a-1) |
=
| a+1 |
| a-1 |
| a |
| a-1 |
=
| a+1-a |
| a-1 |
=
| 1 |
| a-1 |
点评:分式的加减运算中,如果是同分母分式,那么分母不变,把分子直接相加减即可;如果是异分母分式,则必须先通分,把异分母分式化为同分母分式,然后再相加减.
练习册系列答案
相关题目