题目内容
先化简,再求值:
÷(m-
)•
,其中m是方程2m2+4m-1=0的解.
| m2-6m+9 |
| m2-4 |
| 4m-9 |
| m-2 |
| 1 |
| m |
分析:首先计算括号内的分式,把除法转化成乘法运算,然后进行分式的乘法运算即可化简,然后把已知的式子变形成m2+2m=
,代入即可求解.
| 1 |
| 2 |
解答:解:原式=
÷
•
=
÷
•
=
•
•
=
=
,
∵2m2+4m-1=0,
∴m2+2m=
,
∴原式=
=2.
| (m-3)2 |
| (m+2)(m-2) |
| m(m-2)-(4m-9) |
| m-2 |
| 1 |
| m |
=
| (m-3)2 |
| (m+2)(m-2) |
| (m-3)2 |
| m-2 |
| 1 |
| m |
=
| (m-3)2 |
| (m+2)(m-2) |
| m-2 |
| (m-3)2 |
| 1 |
| m |
=
| 1 |
| m(m+2) |
=
| 1 |
| m2+2m |
∵2m2+4m-1=0,
∴m2+2m=
| 1 |
| 2 |
∴原式=
| 1 | ||
|
点评:考查了分式的化简求值,解答此题的关键是把分式化到最简,然后代值计算.
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