题目内容
计算:(注:能用简便运算必须简便运算,否则不给分)①3
| 1 |
| 2 |
| 1 |
| 3 |
| 2 |
| 3 |
| 1 |
| 2 |
②4×(
| 4 |
| 5 |
| 3 |
| 4 |
| 1 |
| 2 |
③-(-52)+|-2|÷(-
| 2 |
| 3 |
④137×
| 3 |
| 4 |
| 1 |
| 2 |
| 1 |
| 4 |
⑤
| 3 | -8 |
|
⑥6÷(
| 3 |
| 2 |
| 1 |
| 3 |
| 5 |
| 6 |
分析:①②③④⑤⑥分别根据实数的运算法则计算即可求解.解题时注意利用乘法的分配律使计算简便.
解答:解:①原式=3
+
+2
-
=(3
-
)+(
+2
)
=3+3=6;
②原式=4×(-10)×(
-
+
)
=-40×(
-
+
)
=-32+30-20
=-22;
③原式=25+2×(-
)-4
=25-3-4
=18;
④原式=137×
+137×
-137×
=137×(
+
-
)
=137×0
=0;
⑤原式=-2+
-2
=-4+
=-3
;
⑥原式=6÷(
+
)
=6÷2
=3.
| 1 |
| 2 |
| 1 |
| 3 |
| 2 |
| 3 |
| 1 |
| 2 |
=(3
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 2 |
| 3 |
=3+3=6;
②原式=4×(-10)×(
| 4 |
| 5 |
| 3 |
| 4 |
| 1 |
| 2 |
=-40×(
| 4 |
| 5 |
| 3 |
| 4 |
| 1 |
| 2 |
=-32+30-20
=-22;
③原式=25+2×(-
| 3 |
| 2 |
=25-3-4
=18;
④原式=137×
| 3 |
| 4 |
| 1 |
| 2 |
| 1 |
| 4 |
=137×(
| 3 |
| 4 |
| 1 |
| 2 |
| 1 |
| 4 |
=137×0
=0;
⑤原式=-2+
| 8 |
| 9 |
=-4+
| 8 |
| 9 |
=-3
| 1 |
| 9 |
⑥原式=6÷(
| 3 |
| 2 |
| 1 |
| 2 |
=6÷2
=3.
点评:此题主要考查了实数的运算.无理数的运算法则与有理数的运算法则是一样的.解决此类题目的关键是熟练掌握乘方、开立方、绝对值等考点的运算.
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