题目内容
分式计算:
(1)(-
)2÷
×
;
(2)
+
-
;
(3)先化简,(1+
)÷
,并任选一个你喜欢的数x代入求值.
(1)(-
| a |
| b |
| 3ac |
| 4b |
| 2b2 |
| 3a |
(2)
| 4 |
| x2-4 |
| 2 |
| x+2 |
| 1 |
| x-2 |
(3)先化简,(1+
| 1 |
| x+1 |
| x+2 |
| x2-1 |
考点:分式的化简求值,分式的混合运算
专题:
分析:(1)先算乘方,再把除法转化成乘法,最后约分即可;
(2)先通分,再把分子相加减,分母不变即可;
(3)先把除法转化成乘法,然后约分,再任选一个不等于±1的数代入求值即可.
(2)先通分,再把分子相加减,分母不变即可;
(3)先把除法转化成乘法,然后约分,再任选一个不等于±1的数代入求值即可.
解答:解:(1)(-
)2÷
×
=
•
•
=
,
(2)
+
-
=
+
-
=
=
,
(3)(1+
)÷
=(
)•
=x-1
当x=0时,原式=x-1=-1.
| a |
| b |
| 3ac |
| 4b |
| 2b2 |
| 3a |
=
| a2 |
| b2 |
| 4b |
| 3ac |
| 2b2 |
| 3a |
=
| 8b |
| 9c |
(2)
| 4 |
| x2-4 |
| 2 |
| x+2 |
| 1 |
| x-2 |
=
| 4 |
| (x+2)(x-2) |
| 2(x-2) |
| (x+2)(x-2) |
| (x+2) |
| (x+2)(x-2) |
=
| x-2 |
| (x+2)(x-2) |
=
| 1 |
| x+2 |
(3)(1+
| 1 |
| x+1 |
| x+2 |
| x2-1 |
=(
| x+1+1 |
| x+1 |
| (x+1)(x-1) |
| x+2 |
=x-1
当x=0时,原式=x-1=-1.
点评:此题考查了分式的化简和运算,用到的知识点是分式混合运算的性质和法则,取喜欢的数代入求值时,要特注意原式及化简过程中的每一步都有意义.
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