题目内容
8.| A. | $\left\{\begin{array}{l}{x-1>0}\\{x+2≤0}\end{array}\right.$ | B. | $\left\{\begin{array}{l}{x+1>0}\\{x-2≤0}\end{array}\right.$ | C. | $\left\{\begin{array}{l}{x+1≥0}\\{x-2<0}\end{array}\right.$ | D. | $\left\{\begin{array}{l}{x-1≤0}\\{x+2<0}\end{array}\right.$ |
分析 由数轴可得表示的解集为-1<x≤2,把各个选项求出解集,即可解答.
解答 解:A、$\left\{\begin{array}{l}{x-1>0}\\{x+2≤0}\end{array}\right.$的解集为空集,故错误;
B、$\left\{\begin{array}{l}{x+1>0}\\{x-2≤0}\end{array}\right.$的解集为-1<x≤2,故正确;
C、$\left\{\begin{array}{l}{x+1≥0}\\{x-2<0}\end{array}\right.$的解集为-1≤x<2,故错误;
D、$\left\{\begin{array}{l}{x-1≤0}\\{x+2<0}\end{array}\right.$的解集为x<-2,故错误;
故选:B.
点评 本题考查了在数轴上表示不等式的解集,解决本题的关键是求出不等式组的解集.
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