题目内容
填上适当的数,使下面各等式成立:
(1)x2+3x+______=(x+______)2;
(2)______-3x+
=(3x______)2;
(3)4x2+______+9=(2x______)2;
(4)x2-px+______=(x-______)2;
(5)x2+
x+______=(x+______)2.
(1)x2+3x+______=(x+______)2;
(2)______-3x+
| 1 |
| 4 |
(3)4x2+______+9=(2x______)2;
(4)x2-px+______=(x-______)2;
(5)x2+
| b |
| a |
(1)x2+3x+
=(x+
)2;
(2)9x2-3x+
=(3x-
)2;
(3)4x2+12x+9=(2x+3)2;
(4)x2-px+
=(x-
)2;
(5)x2+
x+
=(x+
)2.
故答案是
,
,9x2,-
,12x,+3,
,
,
,
.
| 9 |
| 4 |
| 3 |
| 2 |
(2)9x2-3x+
| 1 |
| 4 |
| 1 |
| 2 |
(3)4x2+12x+9=(2x+3)2;
(4)x2-px+
| p2 |
| 4 |
| p |
| 2 |
(5)x2+
| b |
| a |
| b2 |
| 4a2 |
| b |
| 2a |
故答案是
| 9 |
| 4 |
| 3 |
| 2 |
| 1 |
| 2 |
| p2 |
| 4 |
| p |
| 2 |
| b2 |
| 4a2 |
| b |
| 2a |
练习册系列答案
相关题目