题目内容
先化简,再求值:| x |
| x2-1 |
| 1 |
| x-1 |
| 3 |
分析:分别化简代数式和x的值,代入计算.
解答:解:
÷(1+
)=
÷
=
×
=
.
x=2cos30°-(
)0=2×
-1=
-1.
∴当x=
-1时,
原式=
=
=
=
.
| x |
| x2-1 |
| 1 |
| x-1 |
| x |
| x2-1 |
| x-1+1 |
| x-1 |
=
| x |
| (x+1)(x-1) |
| x-1 |
| x |
=
| 1 |
| x+1 |
x=2cos30°-(
| 3 |
| ||
| 2 |
| 3 |
∴当x=
| 3 |
原式=
| 1 |
| x+1 |
| 1 | ||
|
| 1 | ||
|
| ||
| 3 |
点评:本题考查了实数的运算及分式的化简求值.在分式化简过程中,首先要弄清楚运算顺序,先去括号,再进行分式的乘除.
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