题目内容
化简或计算
(1)
+
(2)
÷(
-x-2).
(1)
| m2 |
| m-2 |
| 4 |
| 2-m |
(2)
| x-3 |
| 2x-4 |
| 5 |
| x-2 |
分析:(1)先把后面的分式的分母变形得到原式=
-
,再进行同分母的分式的减法运算,然后把分子分解后约分即可;
(2)先把括号内通分后分解因式,再把除法化为乘法,然后约分即可.
| m2 |
| m-2 |
| 4 |
| m-2 |
(2)先把括号内通分后分解因式,再把除法化为乘法,然后约分即可.
解答:解:(1)原式=
-
=
=
=m+2;
(2)原式=
÷
=
÷
=-
•
=-
.
| m2 |
| m-2 |
| 4 |
| m-2 |
=
| m2-4 |
| m-2 |
=
| (m+2)(m-2) |
| m-2 |
=m+2;
(2)原式=
| x-3 |
| 2(x-2) |
| 5-(x+2)(x-2) |
| x-2 |
=
| x-3 |
| 2(x-2) |
| -(x2-9) |
| x-2 |
=-
| x-3 |
| 2(x-2) |
| x-2 |
| (x+3)(x-3) |
=-
| 1 |
| 2x+6 |
点评:本题考查了分式的混合运算:先进行分式的乘除运算,然后进行分式的加减运算;有括号先计算括号内的运算.
练习册系列答案
相关题目