题目内容
计算:[| 2 |
| 3x |
| 2 |
| x+y |
| x+y |
| 3x |
| x-y |
| x |
分析:仔细观察这道题,可以发现,把小括号中的-x-y看作是-(x+y)会给题目的计算带来方便,而如果一味的先通分,再约分,反而会使问题计算过程变得复杂.
解答:解:[
-
(
-x-y)]÷
=[
-
•
+
•(x+y)]•
=(
-
+2)•
=
故答案为
.
| 2 |
| 3x |
| 2 |
| x+y |
| x+y |
| 3x |
| x-y |
| x |
=[
| 2 |
| 3x |
| 2 |
| x+y |
| x+y |
| 3x |
| 2 |
| x+y |
| x |
| x-y |
=(
| 2 |
| 3x |
| 2 |
| 3x |
| x |
| x-y |
=
| 2x |
| x-y |
故答案为
| 2x |
| x-y |
点评:本题主要考查分式的混合运算,通分、因式分解和约分是解答的关键.
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