题目内容
先化简,再求值:
-
÷
,选取一个你认为合适的数作为x的值代入求值.
| x |
| x+2 |
| x2+x+1 |
| x+2 |
| x2-1 |
| x-1 |
分析:先将除法转化为乘法,约分后再通分,然后将数值代入求值,要注意,所取值不能使每一步的分母为0.
解答:解:原式=
-
•
=
-
•
=
-
•
=
-
=
=
=-
.
当x=3时,原式=-
=-
.
| x |
| x+2 |
| x2+x+1 |
| x+2 |
| x-1 |
| (x-1)(x+1) |
=
| x |
| x+2 |
| x2+x+1 |
| x+2 |
| 1 |
| x+1 |
=
| x(x+1) |
| (x+2)(x+1) |
| x2+x+1 |
| x+2 |
| 1 |
| x+1 |
=
| x(x+1) |
| (x+2)(x+1) |
| x2+x+1 |
| (x+2)(x+1) |
=
| x2+x-x2-x-1 |
| (x+2)(x+1) |
=
| -1 |
| (x+2)(x+1) |
=-
| 1 |
| x2+3x+2 |
当x=3时,原式=-
| 1 |
| 9+9+2 |
| 1 |
| 20 |
点评:本题考查了分式的化简求值,熟悉因式分解及通分、约分是解题的关键.
练习册系列答案
相关题目