题目内容
先化简,再求值:
-
•
,其中x=1.
| x |
| x+1 |
| x+3 |
| x+1 |
| x2-2x+1 |
| x2+4x+3 |
分析:将分子、分母因式分解,约分,通分,再代值计算.
解答:解:
-
•
=
-
•
=
-
=
=
,
当x=1时,原式=
=
.
| x |
| x+1 |
| x+3 |
| x+1 |
| x2-2x+1 |
| x2+4x+3 |
=
| x |
| x+1 |
| x+3 |
| x+1 |
| (x-1)2 |
| (x+1)(x+3) |
=
| x |
| x+1 |
| (x-1)2 |
| (x+1)2 |
=
| x(x+1)-(x-1)2 |
| (x+1)2 |
=
| 3x-1 |
| (x+1)2 |
当x=1时,原式=
| 3-1 |
| (1+1)2 |
| 1 |
| 2 |
点评:本题考查了分式的化简求值.分式的混合运算需特别注意运算顺序及符号的处理,也需要对通分、分解因式、约分等知识点熟练掌握.
练习册系列答案
相关题目