题目内容
计算:1992+
-
+
-
+
-
+…+1990
-1991
.
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| 16 |
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考点:有理数的加减混合运算
专题:常规题型
分析:分析式子:
,
,
…1990
,进行拆项:1992+(
+2+
+4+
+6+
+…+1990+
);-
,-
,-
…-1991
,进行拆项:-(
+2+
+4+6+
+…+1990+
),然后计算即可.
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| 5 |
| 2 |
| 9 |
| 2 |
| 1 |
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| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
| 4 |
| 3 |
| 10 |
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| 16 |
| 3 |
| 1 |
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解答:解:1992+
-
+
-
+
-
+…+1990
-1991
.
=1992+(
+2+
+4+
+6+
+…+1990+
)-(
+2+
+4+6+
+…+1990+
)
=1992+(
-
)×996
=1992-
×996
=1992-830
=1162.
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| 2 |
| 4 |
| 3 |
| 5 |
| 2 |
| 10 |
| 3 |
| 9 |
| 2 |
| 16 |
| 3 |
| 1 |
| 2 |
| 1 |
| 3 |
=1992+(
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
| 4 |
| 3 |
| 4 |
| 3 |
| 4 |
| 3 |
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| 3 |
=1992+(
| 1 |
| 2 |
| 4 |
| 3 |
=1992-
| 5 |
| 6 |
=1992-830
=1162.
点评:此题考查的是有理数的混合运算,解决此题的关键是:将两组分数进行拆项.
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