题目内容
若
=2,则
-
= .
| x-y |
| x+y |
| x-y |
| x+y |
| 2(x+y) |
| 3(x-y) |
考点:分式的化简求值
专题:
分析:根据已知条件得到
=
,所以把
=2、
=
代入所求的代数式进行求值即可.
| x+y |
| x-y |
| 1 |
| 2 |
| x-y |
| x+y |
| x+y |
| x-y |
| 1 |
| 2 |
解答:解:∵
=2,
∴
=
,
∴
-
=2-
×
=2-
×
=
.
故答案是:
.
| x-y |
| x+y |
∴
| x+y |
| x-y |
| 1 |
| 2 |
∴
| x-y |
| x+y |
| 2(x+y) |
| 3(x-y) |
| 2 |
| 3 |
| x+y |
| x-y |
| 2 |
| 3 |
| 1 |
| 2 |
| 5 |
| 3 |
故答案是:
| 5 |
| 3 |
点评:本题考查了分式的化简求值.解答此题的关键是把分式化到最简,然后代值计算.
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