题目内容
根据下列条件,确定锐角α的值:
(1)cos(α+10°)-
=0;(2)sin2α-
sinα+
=0.
(1)cos(α+10°)-
| ||
| 2 |
| ||
| 2 |
| ||
| 4 |
(1)∵cos(α+10°)-
=0,
∴cos(α+10°)=
,
∴α+10°=30°,
∴α=20°.
(2)∵sin2α-
sinα+
=0.
∴(sinα-
)(sinα-
)=0,
∴sinα-
=0或sinα-
=0.
α=30°或α=60°.
| ||
| 2 |
∴cos(α+10°)=
| ||
| 2 |
∴α+10°=30°,
∴α=20°.
(2)∵sin2α-
| ||
| 2 |
| ||
| 4 |
∴(sinα-
| 1 |
| 2 |
| ||
| 2 |
∴sinα-
| 1 |
| 2 |
| ||
| 2 |
α=30°或α=60°.
练习册系列答案
相关题目