题目内容
先化简(1+| 1 |
| x-1 |
| x |
| x2-1 |
分析:本题的关键是正确进行分式的通分、约分,并准确代值计算.
解答:解:原式=(
+
)×
=
×
=x+1,
当x=2006时,原式=2006+1=2007.
| x-1 |
| x-1 |
| 1 |
| x-1 |
| (x+1)(x-1) |
| x |
=
| x |
| x-1 |
| (x+1)(x-1) |
| x |
=x+1,
当x=2006时,原式=2006+1=2007.
点评:代自己喜欢的值时要注意该值满足分式分母不为0这一条件.
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