题目内容
若
=
=
,则
= .
| x |
| 2 |
| y |
| 3 |
| z |
| 4 |
| 2x+y-3z |
| x-y+2z |
考点:比例的性质
专题:
分析:设
=
=
=k,则x=2k,y=3k,z=4k,代入求出即可.
| x |
| 2 |
| y |
| 3 |
| z |
| 4 |
解答:解:设
=
=
=k,
则x=2k,y=3k,z=4k,
=
=-
,
故答案为:-
.
| x |
| 2 |
| y |
| 3 |
| z |
| 4 |
则x=2k,y=3k,z=4k,
| 2x+y-3z |
| x-y+2z |
| 4k+3k-12k |
| 2k-3k+8k |
| 5 |
| 7 |
故答案为:-
| 5 |
| 7 |
点评:本题考查了比例的性质的应用,主要考查学生能否选择适当的方法求出代数式的值.
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