ÌâÄ¿ÄÚÈÝ

2009Äê´º½ÚÁª»¶Íí»áÉÏ£¬ÁõÇ«µÄħÊõ±íÑݼ¤ÆðÁËÈËÃÇÇ¿Á񵀼̮æÐÄ£¬²¢ÔÚÈ«¹ú·¶Î§ÄÚÏÆÆðÁËħÊõ±íÑݵÄÈȳ±£®ÔÚѧУ¿Æ¼¼½Ú»î¶¯ÖУ¬Ò»Î»¾ÅÄ꼶ͬѧ¸øµÍÄ꼶ͬѧ±íÑÝÁËÒ»×黯ѧСħÊõ£¬ÇëÄãÀûÓÃËùѧ»¯Ñ§ÖªÊ¶½Ò¿ªÆäÖÐÖ®ÃÕ£®

¡¡¡¡Ä§ÊõÒ»¡°Ææ»¨±äÉ«¡±

µÀ¾ßÈçͼËùʾ£¬¸ÃħÊõÖпɹ۲쵽¡°ÌúÊ÷¡±ÉϽþÓÐÎÞÉ«·Ó̪ÈÜÒºµÄÃÞÍÅÓɰ×É«±äΪ________É«£®¸ÃħÊõÖÐûÓÐÉæ¼°µÄÐÔÖÊÊÇ________(Ìî×ÖĸÐòºÅ)£®

A£®°±·Ö×ÓÊDz»¶ÏÔ˶¯µÄ

B£®°±·Ö×ÓÓÐÒ»¶¨µÄÖÊÁ¿

C£®Å¨°±Ë®¾ßÓлӷ¢ÐÔ

D£®°±ÆøµÄË®ÈÜÒºÏÔ¼îÐÔ

¡¡¡¡Ä§Êõ¶þ¡°Æ¿Í̼¦µ°¡±

µÀ¾ßÈçͼËùʾ£¬½«×¢ÉäÆ÷ÖÐNaOHŨÈÜҺעÈëÆ¿ÖУ¬Æ¬¿Ìºó»á¿´µ½¼¦µ°±»¡°ÍÌ¡±ÈëÆ¿ÖУ®¸ÃħÊõÖÐÉæ¼°µÄ»¯Ñ§·´Ó¦Îª________(Óû¯Ñ§·½³Ìʽ±íʾ)£®

´ð°¸£º
½âÎö£º

¡¡¡¡Ä§ÊõÒ»£ººì¡¡B

¡¡¡¡Ä§Êõ¶þ£º2NaOH£«CO2Na2CO3£«H2O


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
29¡¢2009Äê´º½ÚÁª»¶Íí»áÉÏ£¬ÁõÇ«µÄħÊõ±íÑݼ¤ÆðÁËÈËÃÇÇ¿Á񵀼̮æÐÄ£¬²¢ÔÚÈ«¹ú·¶Î§ÄÚÏÆÆðÁËħÊõ±íÑݵÄÈȳ±£®ÔÚѧУ¿Æ¼¼½Ú»î¶¯ÖУ¬Ò»Î»¾ÅÄ꼶ͬѧ¸øµÍÄ꼶ͬѧ±íÑÝÁËÒ»×黯ѧСħÊõ£¬ÇëÄãÀûÓÃËùѧ»¯Ñ§ÖªÊ¶½Ò¿ªÆäÖÐÖ®ÃÕ£®

ħÊõÒ»¡°Ææ»¨±äÉ«¡±£ºµÀ¾ßÈçͼ1Ëùʾ£¬¸ÃħÊõÖпɹ۲쵽¡°ÌúÊ÷¡±ÉϽþÓÐÎÞÉ«·Ó̪ÊÔÒºµÄÃÞÍÅÓɰ×É«±äΪ
ºì
É«£®¸ÃħÊõÖÐûÓÐÉæ¼°µÄÐÔÖÊÊÇ
B
£¨Ìî×ÖĸÐòºÅ£©£®
A£®°±·Ö×ÓÊDz»¶ÏÔ˶¯µÄB£®°±·Ö×ÓÓÐÒ»¶¨ÖÊÁ¿
C£®Å¨°±Ë®¾ßÓлӷ¢ÐÔD£®°±ÆøµÄË®ÈÜÒºÏÔ¼îÐÔ
ħÊõ¶þ¡°Æ¿Í̼¦µ°¡±£ºµÀ¾ßÈçͼ2Ëùʾ£¬½«×¢ÉäÆ÷ÖÐNaOHŨÈÜҺעÈëÆ¿ÖУ¬Æ¬¿Ìºó»á¿´µ½¼¦µ°±»¡°ÍÌ¡±ÈëÆ¿ÖУ®¸ÃħÊõÖÐÉæ¼°µÄ»¯Ñ§·´Ó¦Îª£¨Óû¯Ñ§·½³Ìʽ±íʾ£©
2NaOH+CO2=Na2CO3+H2O
£®
ħÊõÈý¡°Ë®ÖÐÉú»ð¡±£ºµÀ¾ßÈçͼ3Ëùʾ£¬µ±Í¨¹ýµ¼¹ÜÏòÈÈË®ÖÐͨÈëÑõÆøÊ±£¬°×Á×ÔÚË®ÏÂȼÉÕ£®¸ÃħÊõ˵Ã÷ȼÉÕÐèÒªµÄÌõ¼þΪ£º¢Ù
ÎïÖʾßÓпÉȼÐÔ
£»¢Ú
ÎïÖʵÄζȴﵽÆä×Å»ðµã
£»¢Û
ÎïÖÊÓëÑõÆø³ä·Ö½Ó´¥
£®
ħÊõËÄ¡°¡®ÇåË®¡¯±ä¡®Å£ÄÌ¡¯¡±£ºµÀ¾ßÈçͼ4Ëùʾ£¬µ±AÈÜÒº¼Óµ½ÉÕ±­ÖУ¬ÎÞÉ«ÈÜÒº±ä³É°×É«×ÇÒº£®ÔòA¡¢BµÄ¿ÉÄÜ×éºÏ£¨Ð´Ò»×飩£ºAΪ
H2SO4£»
£»BΪ
BaCl2»òBa£¨NO3£©2
£®µ±AΪËáÈÜҺʱ£¬ÔòA¡¢BµÄ¿ÉÄÜ×éºÏ£¨Ð´Ò»×飩£ºAΪ
ϡHCl
£»BΪ
AgNO3
£®
19¡¢2009Äê´º½ÚÁª»¶Íí»áÉÏ£¬ÁõÇ«µÄħÊõ±íÑݼ¤ÆðÁËÈËÃÇµÄºÃÆæÐÄ£®ÖØÇìÒ»ÖгõÈýij°àͬѧÔÚ¹úÇìÍí»áÉϱíÑÝÁËÒ»×黯ѧСħÊõ£¬ÇëÄãÓû¯Ñ§ÖªÊ¶½Ò¿ªÆäÖÐÖ®ÃÕ£®

ħÊõÒ»¡°Ææ»¨±äÉ«¡±¸ÃħÊõÖпɹ۲쵽¡°ÌúÊ÷¡±ÉϽþÓÐÎÞÉ«·Ó̪ÊÔÒºµÄÃÞÍÅÓɰ×É«±äΪºìÉ«£®¸ÃħÊõÖÐûÓÐÉæ¼°µÄÐÔÖÊÊÇ
B
£¨ÌîÐòºÅ£©£®
A£®°±·Ö×ÓÊDz»¶ÏÔ˶¯µÄ                    B£®°±·Ö×ÓÓÐÒ»¶¨µÄÖÊÁ¿
C£®Å¨°±Ë®¾ßÓлӷ¢ÐÔ                       D£®°±·Ö×ÓµÄÔ˶¯ËÙÂʱȷÓ̪Á£×Ó¿ì
ħÊõ¶þ¡°ÇåË®¡±±ä¡°Å£ÄÌ¡±¸ÃħÊõÉæ¼°·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
CO2+Ca£¨OH£©2¨TCaCO3¡ý+H2O£¨ºÏÀí¼´¿É£©
£®
ħÊõÈý¡°ÎÞÖÐÉúÓС±µÀ¾ßÈçͼ¢ÛËùʾ£¬ÏàͬÌõ¼þÏ£¬ÏòA¡¢BÁ½¸öÌå»ýÏàͬµÄ¼¯ÆøÆ¿Öзֱð³äÂúÎÞÉ«µÄÒ»Ñõ»¯µªÆøÌåºÍÑõÆø£¬³é×ß²£Æ¬£¬Á½Æ¿¾ùÓÉÆ¿¿ÚÏòÆ¿µ×Öð½¥³äÂúºì×ØÉ«ÆøÌ壮¸ÃħÊõÉæ¼°·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
2NO+O2¨T2NO2
£®COºÍC³£×÷»¹Ô­¼ÁµÄÔ­ÒòÊÇ£ºÔÚ·´Ó¦ÖÐCÔªËØµÄ»¯ºÏ¼Û¶¼Éý¸ß£¬ÓÉ´ËÍÆ¶Ï¸Ã·´Ó¦ÖеĻ¹Ô­¼ÁÊÇ
NO
£®
ÒÑÖª£ºÏàͬÌõ¼þÏ£¬ÏàµÈÌå»ýµÄÆøÌåËùº¬µÄ·Ö×ÓÊýÄ¿ÏàµÈ£®·´Ó¦Íê±Ïºó£¬Æ¿ÖÐÊ£ÓàµÄÆøÌåΪ
NO¡¢NO2
£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø