ÌâÄ¿ÄÚÈÝ

ÎÒ¹ú¸ÖÌúÄê²úÁ¿¾ÓÊÀ½çµÚÒ»£¬Îª¹úÃñ¾­¼ÃµÄ·¢Õ¹µì¶¨Á˼áʵµÄ»ù´¡¡£ ¹¤ÒµÉÏÒÔ¿ÕÆø¡¢Ìú¿óʯ¡¢Ê¯»ÒʯºÍ_____ΪԭÁÏÀ´Ò±Á¶ÉúÌú¡£Ìú¿óʯұÁ¶³ÉÌúÊÇÒ»¸ö¸´ ÔӵĹý³Ì£¬Ä³Á¶Ìú³§ÓóàÌú¿óÀ´Á¶Ìú£¬ÆäÁ¶ÌúµÄÖ÷ÒªÔ­ÀíÊÇ_____£¨Óû¯Ñ§·½³Ìʽ±íʾ£©¡£

ÒÑ֪ijÌúÐâµÄ³É·ÖΪ Fe2O3•xH2O ºÍ FeCO3£¬Ä³ÐËȤС×éµÄͬѧÔÚÀÏʦָµ¼Ï²ⶨÆä×é³É¡£

£¨Ìá³öÎÊÌ⣩

£¨1£©¸ù¾ÝÌúÉúÐâµÄ³É·ÖÍÆ²â£¬²Î¼Ó·´Ó¦µÄ³ýÁË¿ÕÆøÖеÄÑõÆøºÍË®ÕôÆøÖ®Í⣬»¹ÓÐ_____ ²Î¼ÓÁË·´Ó¦¡£

£¨2£©ÈçºÎÈ·¶¨´ËÌúÐâµÄ×é³É£¿

£¨²éÔÄ×ÊÁÏ£©

¢ÙFe2O3•xH2O ʧȥ½á¾§Ë®Î¶ÈΪ 110¡æ£¬FeCO3 ÔÚ 282¡æ·Ö½âΪ FeO ºÍ CO2£¬Fe2O3 ÔÚ 300¡æÊ±²»·Ö½â¡£

¢Ú±¾ÊµÑéÌõ¼þÏ£¬¶þÑõ»¯Ì¼ÆøÌåµÄÃܶÈΪ 1.80g/L£¬×°ÖÃÄÚ¿ÕÆøÖеÄË®ÕôÆøºÍ¶þÑõ»¯Ì¼¶ÔÏà ¹ØÊý¾Ý²â¶¨µÄÓ°Ïì¿ÉºöÂÔ²»¼Æ¡£

£¨Éè¼Æ·½°¸£©ÐËȤС×éµÄͬѧÉè¼ÆÁËÈçͼËùʾµÄʵÑé×°Ö㨼гÖÒÇÆ÷Ê¡ÂÔ£©½øÐÐʵÑé¡££¨B¡¢D ×°ÖÃÖÐÒ©Æ·¾ù×ãÁ¿£©

¢ñ

¢ò

A ×°ÖõÄÖÊÁ¿/g

55.44

53.92

B ×°ÖõÄÖÊÁ¿/g

102.00

103.08

C ×°ÖöÁÊý/mL

0

244.4

£¨ÊµÑé²½Ö裩

¢ÙÁ¬½ÓÒÇÆ÷£¬²¢¼ì²é×°ÖÃÆøÃÜÐÔ¡£

¢Úȡһ¶¨Á¿´ËÌúÐâÑùÆ·£¬×¼È·³ÆµÃÆäÖÊÁ¿Îª 5.44g¡£

¢Û°´Í¼ËùʾװÈëÒ©Æ·£¬²âÁ¿²¢¼Ç¼Ïà¹ØÊý¾Ý I¡£

¢ÜÁ¬½Ó A¡¢B¡¢C ×°Ö㬹رÕ×°Öà A ÖлîÈû£¬C ×°ÖöÁÊýºó£¬¿ØÖÆ A ×°ÖÃÔÚ 300¡æ½øÐÐʵ Ñé¡£µ±¹Û²ìµ½C×°ÖÃÖÐÓÐ_____ÏÖÏóʱ£¬Í£Ö¹¼ÓÈÈ£¬´ý×°ÖÃÀäÈ´ºó£¬ÔٴβâÁ¿²¢¼Ç¼Ïà¹ØÊý¾Ý II¡£

£¨Ïà¹ØÊý¾Ý£©£¨¼ûÉÏ±í£©

£¨ÎÊÌâÌÖÂÛ£©

£¨1£©Á¿Æø¹ÜÖÐË®ÃæÉÏÓ͵Ä×÷ÓÃÊÇ_____¡£ ·ÖÎö¼ÆËã²âÁ¿µÄÊý¾Ý£¬FeCO3µÄÖÊÁ¿Îª_____g£¬x Ϊ_____¡£

£¨2£©ÏÂÁÐÊý¾Ý×éºÏÄÜÈ·¶¨ÑùÆ·×é³ÉµÄÊÇ_____£¨ÌîÐòºÅ£©¡£

¢ÙA¡¢B ×°Ö÷´Ó¦Ç°ºó²âµÃµÄÊý¾Ý ¢ÚA¡¢C ×°Ö÷´Ó¦Ç°ºó²âµÃµÄÊý¾Ý

¢ÛB¡¢C ×°Ö÷´Ó¦Ç°ºó²âµÃµÄÊý¾Ý

£¨ÍØÕ¹Ì½¾¿£©

С»ªÍ¬Ñ§½«ÉÏÊöʵÑéÖÐµÄ C ×°Öû»³É D ×°ÖÃÀ´²â¶¨¶þÑõ»¯Ì¼ÆøÌåµÄÖÊÁ¿£¬²¢¸ù¾Ý²â¶¨µÄÊý ¾ÝÈ·¶¨ÑùÆ·µÄ×é³É¡£Ð¡»ªÍ¬Ñ§Í¨¹ý¶à´Î·´¸´ÊµÑé·¢ÏÖ£¬ÔÚ´ËʵÑéÖУ¬Óà C ×°Öòⶨ¶þÑõ»¯ Ì¼ÆøÌåµÄÌå»ýÓëÓà D ×°Öòⶨ¶þÑõ»¯Ì¼ÆøÌåµÄÖÊÁ¿Ïà±È½Ï£¬µ±Îó²îÊýÖµ¶¼Îª 0.1 ʱ£¬Ç°Õß¶Ô ÊµÑé½á¹ûÓ°ÏìС¡£ÊÔͨ¹ý¼ÆËã˵Ã÷Ô­Òò_____¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø