题目内容


向20g锌样品(杂质不溶于水,也不溶于酸)中加入100g质量分数为19.6%的稀硫酸,恰好完全反应。试计算该锌样品中锌的质量分数(写出计算过程)。


解:设20g锌样品中含有锌的质量为x  ································································· 1分

Zn + H2SO4  == ZnSO4 + H2↑      ································································ 1分

65    98

x   100g×19.6%

=              ······························································ 2分

          x =13g                     ······························································ 1分

锌样品中锌的质量分数=×100%=65%  ····················································· 1分

答: 锌样品中锌的质量分数为65%。


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