ÌâÄ¿ÄÚÈÝ
¾Æ¾«ÓÖ³ÆÎªÒÒ´¼£¬³ý¿ÉÒÔÓÃÓÚÖÆ×÷º¬´¼ÒûÁÏÍâÒ²ÊÇÒ»ÖÖÇå½àȼÁÏ¡£Óõí·ÛÄðÖÆÒÒ´¼µÄ»¯Ñ§·´Ó¦·½³ÌʽÊÇ£º(C6H10O5)n£«nH2O
2nCH3CH2OH£«2nCO2¡ü
[×¢£º(C6H10O5)nµÄÏà¶Ô·Ö×ÓÖÊÁ¿ÊÇ162n ]¡£¼ÆË㣨½á¹û±£Áô1λСÊý£©£º
£¨1£©CH3CH2OHµÄÏà¶Ô·Ö×ÓÖÊÁ¿ÊÇ £»
£¨2£©100©Kµí·ÛÀíÂÛÉÏ¿ÉÒÔÖÆµÃÒÒ´¼µÄÖÊÁ¿ÊǶàÉÙ£¿
£¨3£©¼ÙÉè×í¾Æ¼Ý³µµÄ±ê×¼ÊÇÈËÌåѪҺÖÐÒÒ´¼º¬Á¿³¬¹ý80mg/L¡£ÈôÈËÌåÖÐѪҺռÈËÌåÌåÖØµÄ10%£¨¼ÙÉèѪҺµÄÃܶÈÊÇ£º1kg/L£©£¬Ôò£º
![]()
¢Ù£®Ò»¸öÌåÖØÎª60kgµÄ¼ÝʻԱѪҺÖÐËùº¬ÒÒ´¼µÄ×ÜÖÊÁ¿²»Äܳ¬¹ý¶àÉÙ£¿
¢Ú£®¢ÙÖнá¹ûÏ൱ÓÚÖÊÁ¿·ÖÊýΪ50%µÄ°×¾ÆµÄÖÊÁ¿ÊǶàÉÙ£¿
£¨1£©46
£¨2£©½â£ºÉè100kgµ·ÛÀíÂÛÉÏ¿ÉÒÔÖÆµÃÒÒ´¼µÄÖÊÁ¿ÊÇx
£¨C6H10O5£©n+2NH2O
2NCH3CH2OH+2NCO2¡ü
162n 92n
100kg x
![]()
x¡Ö56.8kg
£¨3£©½â£º¢ÙÉèÒ»¸öÌåÖØÎª60kgµÄ¼ÝʻԱµÄѪҺÖо¿¾¹º¬Á¿×î¶à²»Äܳ¬¹ýµÄÁ¿Îªy
y=(60kg¡Á10%¡Â1kg/L)¡Á80mg/L
=480mg
¢ÚÏ൱ÓÚÖÊÁ¿·ÖÊý50%µÄ°×¾ÆµÄÖÊÁ¿Îªz
Z=480mg³ý50%
=960mg
½âÎö:ÂÔ