ÌâÄ¿ÄÚÈÝ

¾Æ¾«ÓÖ³ÆÎªÒÒ´¼£¬³ý¿ÉÒÔÓÃÓÚÖÆ×÷º¬´¼ÒûÁÏÍâÒ²ÊÇÒ»ÖÖÇå½àȼÁÏ¡£Óõí·ÛÄðÖÆÒÒ´¼µÄ»¯Ñ§·´Ó¦·½³ÌʽÊÇ£º(C6H10O5)n£«nH2O  2nCH3CH2OH£«2nCO2¡ü

[×¢£º(C6H10O5)nµÄÏà¶Ô·Ö×ÓÖÊÁ¿ÊÇ162n ]¡£¼ÆË㣨½á¹û±£Áô1λСÊý£©£º

£¨1£©CH3CH2OHµÄÏà¶Ô·Ö×ÓÖÊÁ¿ÊÇ      £»

£¨2£©100©Kµí·ÛÀíÂÛÉÏ¿ÉÒÔÖÆµÃÒÒ´¼µÄÖÊÁ¿ÊǶàÉÙ£¿

£¨3£©¼ÙÉè×í¾Æ¼Ý³µµÄ±ê×¼ÊÇÈËÌåѪҺÖÐÒÒ´¼º¬Á¿³¬¹ý80mg/L¡£ÈôÈËÌåÖÐѪҺռÈËÌåÌåÖØµÄ10%£¨¼ÙÉèѪҺµÄÃܶÈÊÇ£º1kg/L£©£¬Ôò£º

 

 

¢Ù£®Ò»¸öÌåÖØÎª60kgµÄ¼ÝʻԱѪҺÖÐËùº¬ÒÒ´¼µÄ×ÜÖÊÁ¿²»Äܳ¬¹ý¶àÉÙ£¿

¢Ú£®¢ÙÖнá¹ûÏ൱ÓÚÖÊÁ¿·ÖÊýΪ50%µÄ°×¾ÆµÄÖÊÁ¿ÊǶàÉÙ£¿

 

£¨1£©46

£¨2£©½â£ºÉè100kgµ­·ÛÀíÂÛÉÏ¿ÉÒÔÖÆµÃÒÒ´¼µÄÖÊÁ¿ÊÇx

£¨C6H10O5£©n+2NH2O2NCH3CH2OH+2NCO2¡ü

162n                     92n

  100kg                     x

      

x¡Ö56.8kg

£¨3£©½â£º¢ÙÉèÒ»¸öÌåÖØÎª60kgµÄ¼ÝʻԱµÄѪҺÖо¿¾¹º¬Á¿×î¶à²»Äܳ¬¹ýµÄÁ¿Îªy

y=(60kg¡Á10%¡Â1kg/L)¡Á80mg/L

=480mg

¢ÚÏ൱ÓÚÖÊÁ¿·ÖÊý50%µÄ°×¾ÆµÄÖÊÁ¿Îªz

Z=480mg³ý50%

=960mg

½âÎö:ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø