ÌâÄ¿ÄÚÈÝ

10£®Ä³ºÏ×÷ѧϰС×éµÄͬѧÃÇΪ²â¶¨Ä³Ê¯»ÒʯµÄÖÊÁ¿·ÖÊý£¬½«ÈÜÖÊÖÊÁ¿·ÖÊýΪ7.3%µÄÏ¡ÑÎËá¼ÓÈë10gʯ»ÒʯÑùÆ·ÖУ¬²úÉúÆøÌåµÄÖÊÁ¿Óë¼ÓÈëÏ¡ÑÎËáµÄÖÊÁ¿¹ØÏµÈçͼ2Ëùʾ£¨¼ÙÉèʯ»ÒʯÑùÆ·ÖеÄÔÓÖʲ»º¬¸ÆÔªËØ£¬²»ÓëÏ¡ÑÎËá·´Ó¦£©£®
£¨1£©ÅäÖÆ100gÈÜÖÊÖÊÁ¿·ÖÊýΪ7.3%µÄÏ¡ÑÎËᣬÐèͼ1ËùʾÑÎËáµÄÖÊÁ¿Îª20g£®
£¨2£©¼ÆËã¸Ãʯ»ÒʯÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊý£»
£¨3£©·´Ó¦½áÊøºó£¬ÉÕ±­ÄÚ¸ÆÔªËصÄÖÊÁ¿Îª3g£®

·ÖÎö £¨1£©Ï¡ÊÍǰºóÈÜÖʵÄÖÊÁ¿²»±ä£¬ÉèÐèÒª36.5%µÄŨÑÎËáµÄÖÊÁ¿Îªx£¬Ôò100g¡Á7.3%=36.5%x£¬x=20g£»
£¨2£©´Óͼ2¿ÉÖª£¬·´Ó¦½áÊøºóÉú³ÉÆøÌåµÄÏ¡ÑÎËáµÄÖÊÁ¿Îª75g£¬ÔòHClµÄÖÊÁ¿Îª75g¡Á7.3%£¬ÔÙÓû¯Ñ§·½³Ìʽ¼´¿É¼ÆËã³ö²ÎÓë·´Ó¦µÄ̼Ëá¸ÆµÄÖÊÁ¿£¬½ø¶ø¿ÉÇó³öÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊý£»
£¨3£©·´Ó¦Ç°ºóÔªËØµÄÖÊÁ¿²»±ä£¬·´Ó¦Ç°ºó£¬ÉÕ±­ÄÚ¸ÆÔªËØÃ»ÓÐËðʧ£¬¹Ê·´Ó¦ºóÉÕ±­ÖиÆÔªËصÄÖÊÁ¿²»±ä£®

½â´ð ½â£º£¨1£©Ï¡ÊÍǰºóÈÜÖʵÄÖÊÁ¿²»±ä£¬ÉèÐèÒª36.5%µÄŨÑÎËáµÄÖÊÁ¿Îªx£¬Ôò100g¡Á7.3%=36.5%x£¬x=20g£»¹ÊÌ20£»
£¨2£©Éèʯ»ÒʯÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿Îªx
CaCO3+2HCl=CaCl2+H2O+CO2¡ü
100   73
x   75g¡Á7.3%
$\frac{100}{73}=\frac{x}{75g¡Á7.3%}$
x=7.5g
ʯ»ÒʯÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊýΪ£º$\frac{7.5g}{10g}¡Á100%$=75%
´ð£ºÊ¯»ÒʯÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊýΪ75%£»
£¨3£©·´Ó¦Ç°ºóÔªËØµÄÖÊÁ¿²»±ä£¬·´Ó¦Ç°ºó£¬ÉÕ±­ÄÚ¸ÆÔªËØÖÊÁ¿²»±ä£¬¹Ê¸ÆÔªËØÖÊÁ¿Îª£º7.5g¡Á40%=3g£»
¹ÊÌ3g£®

µãÆÀ ±¾ÌâÖ÷Òª¿¼²éÁËÈÜÖʵÄÖÊÁ¿·ÖÊýµÄÏà¹Ø¼ÆËãºÍÒÀ¾Ý»¯Ñ§·½³ÌʽµÄ¼ÆË㣬ÄѶȲ»´ó£¬µ«½â´ðʱҪϸÐļÆË㣮

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø