ÌâÄ¿ÄÚÈÝ

3£®Ê¯ÓÍ×ÊÔ´½ôÕÅÔø¾­ÊÇÖÆÔ¼ÎÒ¹ú·¢Õ¹½Î³µÊÂÒµ£¬ÓÈÆäÊÇÖÆÔ¼½Î³µ½øÈë¼ÒÍ¥µÄÖØÒªÒòËØ£®Ä¿Ç°£¬ÎÒ¹úµÄһЩµØÇøÕýÔÚÖð²½Íƹ㡰³µÓÃÒÒ´¼ÆûÓÍ¡±£¬ÒÒ´¼£¨C2H5OH£©ÍêȫȼÉÕºóÉú³É¶þÑõ»¯Ì¼ºÍË®£¬Æä»¯Ñ§·½³ÌʽΪ£ºC2H5OH+3O2$\frac{\underline{\;µãȼ\;}}{\;}$2CO2+3H2O£®
ÊÔ¼ÆËã³ä·ÖȼÉÕ0.92kgÒÒ´¼ËùÉú³ÉµÄ¶þÑõ»¯Ì¼µÄÖÊÁ¿ÊǶàÉÙ£¿

·ÖÎö ¸ù¾ÝÒÒ´¼µÄÖÊÁ¿£¬ÀûÓû¯Ñ§·½³Ìʽ¿ÉÒÔ½øÐÐÏà¹Ø·½ÃæµÄ¼ÆË㣮

½â´ð ½â£ºÉè0.92kgÒÒ´¼ÍêȫȼÉÕ£¬¿ÉÉú³É¶þÑõ»¯Ì¼µÄÖÊÁ¿Îªx£®
C2H5OH+3O2$\frac{\underline{\;µãȼ\;}}{\;}$2CO2+3H20
 46                           88
0.92kg                        x
$\frac{46}{0.92Kg}=\frac{88}{x}$
x=1.76kg£®
´ð°¸£ºÉú³É¶þÑõ»¯Ì¼µÄÖÊÁ¿Îª1.76kg£®

µãÆÀ ½â´ð±¾ÌâÒª³ä·ÖÀí½â»¯Ñ§·½³ÌʽµÄº¬Ò壬²¢ÇÒÄܹ»¸ù¾Ý»¯Ñ§·½³Ìʽ½øÐÐÏà¹Ø·½ÃæµÄÕýÈ·¼ÆË㣮

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø