Question

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200 g	14.5 g	214.0 g

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Answer 1

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         Fe £« 2HCl= FeCl2 £« H2¡ü

         56                   2

         X                   0.5 g        (1·Ö£©

         X  =  0.5g

         56      2                   (1·Ö£©

                

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