ÌâÄ¿ÄÚÈÝ

ÓÃÕäÖ飨Ö÷Òª³É·ÖCaCO3£©¼Ó¹¤³ÉµÄ¡°ÕäÖé·Û¡±ÊÇÒ»ÖÖÃû¹óÖÐÒ©²Ä¡¢±£½¡Æ·£®¿É½üÄêÀ´Êг¡ÉϳöÏÖÁËһЩ¼ÙðµÄ¡°ÕäÖé·Û¡±£¬½öÓÃÈâÑÛ¹Û²ìÄѱæÕæ¼Ù£®ÎªÁËÏòÏû·ÑÕßÌṩ¼ø±ð·½·¨£¬ÐèÕÒ³öÕæ¼Ù¡°ÕäÖé·Û¡±ÎïÀí¡¢»¯Ñ§ÐÔÖÊÉϵIJîÒ죮¹¤É̾ÖÌṩÁËÕæ¡¢¼Ù¡°ÕäÖé·Û¡±ÑùÆ·£¬ÇëÄãÕ¹¿ªÌ½¾¿£¨Ö»ÒªÐ´³ö²ÂÏë¡¢·½°¸£¬²»ÐèҪ˵³ö·½°¸ÊµÊ©µÄ¾ßÌå½á¹û£©£º²ÂÏëÒ»£ºÕæ¡¢¼Ù¡°ÕäÖé·Û¡±µÄÆøÎ¶¿ÉÄܲ»Í¬£»
·½°¸Ò»£ºÈ¡Ñù£¬·Ö±ðÎÅÎÅËüÃÇµÄÆøÎ¶£¬·Ö±æÆøÎ¶ÓÐÎÞ²îÒ죮
²ÂÏë¶þ£º______£»
·½°¸¶þ£º______£®
²ÂÏëÈý£º______£»
·½°¸Èý£º______£®
¡¾´ð°¸¡¿·ÖÎö£ºÀûÓÃÕæ¡¢¼Ù¡°ÕäÖé·Û¡±µÄÐÔÖʲ»Í¬½øÐÐÇø·Ö£¬ÕâÖÖÐÔÖÊ¿ÉÒÔÊÇÎïÀíÐÔÖÊ£¬Ò²¿ÉÒÔÊÇ»¯Ñ§ÐÔÖÊ£¬±ÈÈçÈܽâÐÔ¡¢ÆøÎ¶¡¢ÄÜ·ñÓëËá·´Ó¦µÈ£»Ìî¿Õʱģ·Â²ÂÏëÒ»¡¢·½°¸Ò»Ìîд£®
½â´ð£º½â£ºÇø·ÖÎïÖÊÒ»°ãÒªÇóÊDzÙ×÷¼òµ¥¡¢ÏÖÏóÃ÷ÏÔ£»ÀûÓÃÕæ¡¢¼Ù¡°ÕäÖé·Û¡±µÄÐÔÖʲ»Í¬½øÐÐÇø·Ö£¬±ÈÈçÈܽâÐÔ¡¢ÆøÎ¶¡¢ÄÜ·ñÓëËá·´Ó¦µÈ£®Ìîд·½Ê½ÒªÒÔ²ÂÏëÒ»¡¢·½°¸Ò»µÄÄÚÈÝΪ±ê×¼£¬¹Ê´ð°¸Îª£ºÕæ¡¢¼Ù¡°ÕäÖé·Û¡±µÄÈܽâÐÔ¿ÉÄܲ»Í¬£»È¡Ñù£¬·Ö±ð½«ËüÃǵķÅÈë×ãÁ¿µÄË®ÖУ¬¹Û²ìÈܽâÐÔÓÐÎÞ²îÒì£®Õæ¡¢¼Ù¡°ÕäÖé·Û¡±µÄÊÇ·ñÓëÑÎËá·´Ó¦Ã°ÆøÅÝ£»È¡Ñù£¬·Ö±ð½«ËüÃǵķÅÈë×°ÓÐÑÎËáµÄÊÔ¹ÜÖУ¬¹Û²ìÆøÅÝÓÐÎÞ²îÒ죮
µãÆÀ£º¼Ç×¡Çø·ÖÎïÖÊÒ»°ãÒªÇóÊDzÙ×÷¼òµ¥¡¢ÏÖÏóÃ÷ÏÔ£»ÀûÓÃÕæ¡¢¼Ù¡°ÕäÖé·Û¡±µÄÐÔÖʲ»Í¬½øÐÐÇø·Ö£¬±ÈÈçÈܽâÐÔ¡¢ÆøÎ¶¡¢ÄÜ·ñÓëËá·´Ó¦µÈ£»×¢ÒâÊéдµÄ¸ñʽºÍÌâÄ¿ÕÕÓ¦£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
СԶͨ¹ý²éÔÄ×ÊÁÏÖªµÀÁËÑÀ¸àµÄÖ÷Òª³É·Ö£®Ëü½«Ò»¶¨±ÈÀýµÄ̼Ëá¸Æ·ÛÄ©ºÍʳÑε¹ÈëСÉÕ±­ÖУ¬È»ºó¼ÓÈëÊÊÁ¿¸ÊÓÍ£¨±£Êª¼Á£©¡¢Ìðζ¼ÁºÍÏ㾫µÈ£¬½Á°è¾ùÔȺóÖÆµÃÑÀ¸à£®
£¨1£©ÑÀ¸àÊÇ
»ìºÏÎï
»ìºÏÎï
£¨Ìî´¿¾»Îï¡¢»ìºÏÎ£®
£¨2£©Ð¡Ô¶²â¶¨×ÔÖÆÑÀ¸à¼°ÆäËûÇå½àÓÃÆ·µÄpH£¬¼Ç¼ÈçÏ£º
ÎïÖÊ ×ÔÖÆÑÀ¸à ½à²ÞÁé ÓÍÎÛ¾»
pH 8 2 12
×ÔÖÆÑÀ¸àÏÔ
¼îÐÔ
¼îÐÔ
£¨Ìî¡°ËáÐÔ¡±¡¢¡°¼îÐÔ¡±¡¢¡°ÖÐÐÔ¡±£©£¬½à²ÞÁé¿Éʹ×ÏɫʯÈïÊÔÒº±ä³É
ºì
ºì
É«£®
£¨3£©Ï±íÁгöÁËÈýÖÖÑÀ¸àĦ²Á¼ÁËùÊôµÄÎïÖÊÀà±ð£®
Á½ÃæÕëÑÀ¸à ÕäÖéÍõÑÀ¸à ÖлªÑÀ¸à
Ħ²Á¼Á ÇâÑõ»¯ÂÁ ̼Ëá¸Æ ¶þÑõ»¯¹è
Ħ²Á¼ÁµÄÎïÖÊÀà±ð
£¨Ö¸Ëá¡¢¼î¡¢ÑΡ¢Ñõ»¯Î
¼î
¼î
ÑÎ
ÑÎ
Ñõ»¯Î
Ñõ»¯Î
£¨4£©ÑÀ¸àÖеÄĦ²Á¼Á֮һ̼Ëá¸Æ¿ÉÒÔÓÃʯ»ÒʯÀ´ÖƱ¸£®Ä³Ñ§ÉúÉè¼ÆÁËÒ»ÖÖÖÆ±¸Ì¼Ëá¸ÆµÄʵÑé·½°¸£¬ÆäÁ÷³ÌͼΪ£º

Çëд³öÉÏÊö·½°¸ÖÐÓйط´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
¢Ù
CaCO3
 ¸ßΠ
.
 
CaO+CO2¡ü
CaCO3
 ¸ßΠ
.
 
CaO+CO2¡ü
£»¢Ú
CaO+H2O=Ca£¨OH£©2
CaO+H2O=Ca£¨OH£©2
£»¢Û
Ca£¨OH£©2+Na2CO3=CaCO3¡ý+2NaOH
Ca£¨OH£©2+Na2CO3=CaCO3¡ý+2NaOH
£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø