题目内容
计算(要求脱式计算)
(1)(27×1
+6
×27)×1.25
(2)〔2-(5.55×1
-2
÷0.4)〕÷0.135.
(1)(27×1
4 |
9 |
5 |
9 |
(2)〔2-(5.55×1
1 |
3 |
7 |
10 |
分析:(1)可运用乘法分配律及交换律计算;
(2)根据四则混合运算的运算顺序计算即可.
(2)根据四则混合运算的运算顺序计算即可.
解答:解:(1)(27×1
+6
×27)×1.25
=(1
+6
)×27×1.25,
=8×1.25×27,
=10×27,
=270;
(2)[2-(5.55×1
-2
÷0.4)]÷0.135
=[2-(5.55×
-2.7÷0.4)]÷0.135,
=[2-(7.4-6.75)]÷0.135,
=[2-0.65]÷0.135,
=1.35÷0.135,
=10.
4 |
9 |
5 |
9 |
=(1
4 |
9 |
5 |
9 |
=8×1.25×27,
=10×27,
=270;
(2)[2-(5.55×1
1 |
3 |
7 |
10 |
=[2-(5.55×
4 |
3 |
=[2-(7.4-6.75)]÷0.135,
=[2-0.65]÷0.135,
=1.35÷0.135,
=10.
点评:当算式中同时含有小数与分数时,要根据式中数据的特点灵活将它们互化后进行计算.
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