题目内容
(2010?天河区)用递等式计算(能简算的要简算).
(1)
+
×10
(2)168.1÷(8.5-0.3)
(3)8.72+2.9+3.1+1.28
(4)
x
+
x
.
(1)
1 |
5 |
3 |
25 |
(2)168.1÷(8.5-0.3)
(3)8.72+2.9+3.1+1.28
(4)
4 |
15 |
2 |
9 |
7 |
9 |
4 |
15 |
分析:(1)先算乘法,再算加法;
(2)先算小括号里面的减法,再算括号外的除法;
(3)运用加法交换律和加法结合律简算;
(4)运用乘法分配律简算.
(2)先算小括号里面的减法,再算括号外的除法;
(3)运用加法交换律和加法结合律简算;
(4)运用乘法分配律简算.
解答:解:(1)
+
×10,
=
+
,
=
;
(2)168.1÷(8.5-0.3),
=168.1÷8.2,
=20.5;
(3)8.72+2.9+3.1+1.28,
=(8.72+1.28)+(2.9+3.1),
=10+6,
=16;
(4)
×
+
×
,
=
×(
+
),
=
×1,
=
.
1 |
5 |
3 |
25 |
=
1 |
5 |
6 |
5 |
=
7 |
5 |
(2)168.1÷(8.5-0.3),
=168.1÷8.2,
=20.5;
(3)8.72+2.9+3.1+1.28,
=(8.72+1.28)+(2.9+3.1),
=10+6,
=16;
(4)
4 |
15 |
2 |
9 |
7 |
9 |
4 |
15 |
=
4 |
15 |
2 |
9 |
7 |
9 |
=
4 |
15 |
=
4 |
15 |
点评:此题是考查四则混合运算,要仔细观察算式的特点,灵活运用一些定律进行简便计算.

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