题目内容

(2012?黄岩区)脱式计算.(能简算的要简算)
(1)1020+270÷18-864
(2)
2
3
÷0.8×
3
4

(3)
1
8
+
5
7
+6.875+
2
7

(4)0.25×64×125%
(5)[
8
15
-(
7
12
-
2
5
)]×
15
14

(6)6.35×0.75+4.65×75%-
3
4
分析:(1)先算除法,再算加法和减法;
(2)把小数化为分数,再计算;
(3)运用加法交换律与结合律简算;
(4)把64看作4×2×8,把百分数化为小数,运用乘法交换律与结合律简算;
(5)先算小括号内的,再算中括号内的,最后算括号外的;
(6)把百分数和和分数化为小数,运用乘法分配律简算.
解答:解:(1)1020+270÷18-864,
=1020+15-864,
=171;

(2)
2
3
÷0.8×
3
4

=
2
3
÷
4
5
×
3
4

=
2
3
×
5
4
×
3
4

=
5
8


(3)
1
8
+
5
7
+6.875+
2
7

=(
1
8
+6.875)+(
5
7
+
2
7
),
=(0.125+6.875)+1,
=7+1,
=8;

(4)0.25×64×125%,
=0.25×4×2×8×1.25,
=(0.25×4)×(8×1.25)×2,
=1×10×1,
=20;

(5)[
8
15
-(
7
12
-
2
5
)]×
15
14

=[
8
15
-
11
60
15
14

=
21
60
×
15
14

=
3
8


(6)6.35×0.75+4.65×75%-
3
4

=6.35×0.75+4.65×0.75-0.75,
=(6.35+4.65-1)×0.75,
=10×0.75,
=7.5.
点评:此题考查了四则混合运算,注意运算顺序和运算法则,灵活运用所学的运算定律简便计算.
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