题目内容
(2006?长汀县)
用递等式计算. 235+24×12 |
2.6÷(0.74-0.24)×2.5 |
|
[1-(
|
分析:本题根据四则混合运算的运算法则计算即可:先算乘除,再算加减,有括号的要先算括号里面的.
解答:解:235+24×12
=235+288,
=523;
2.6÷(0.74-0.24)×2.5
=2.6÷0.5×2.5,
=5.2×2.5,
=13;
×
+
=
+
,
=
+
,
=
;
[1-(
-
)]÷
=[1-(
-
)]÷
,
=[1-
]×
,
=
×
,
=
.
=235+288,
=523;
2.6÷(0.74-0.24)×2.5
=2.6÷0.5×2.5,
=5.2×2.5,
=13;
7 |
8 |
3 |
14 |
1 |
4 |
=
3 |
16 |
1 |
4 |
=
3 |
16 |
4 |
16 |
=
7 |
16 |
[1-(
5 |
6 |
1 |
3 |
2 |
5 |
=[1-(
5 |
6 |
2 |
6 |
2 |
5 |
=[1-
1 |
2 |
5 |
2 |
=
1 |
2 |
5 |
2 |
=
5 |
4 |
点评:在算式中同时含有中括号与小括号时,要先算小括号内的,再算中括号内的.
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