题目内容
47+256+53 | 368-152-48 | 25×17×4 |
2700÷25÷4 | 125×88 | 99×41+41 |
13×75+13×25 | 125×72 | 25×(4+8) |
分析:算式(1)可根据加法交换律进行计算;
算式(2)可根据一个数减两个数,等于用这个数减去这两个数的和的减法性质进行计算;
算式(3)可根据乘法交换律进行计算;
算式(4)可根据一个数除以两个数,等于用这个数除以这两个数的积的除法性质进行计算;
算式(5)可将式的88拆分为8×11进行计算;
算式(6)(7)(9)可根据乘法分配律进行计算;
算式(8)可将72拆分为8×9进行计算.
算式(2)可根据一个数减两个数,等于用这个数减去这两个数的和的减法性质进行计算;
算式(3)可根据乘法交换律进行计算;
算式(4)可根据一个数除以两个数,等于用这个数除以这两个数的积的除法性质进行计算;
算式(5)可将式的88拆分为8×11进行计算;
算式(6)(7)(9)可根据乘法分配律进行计算;
算式(8)可将72拆分为8×9进行计算.
解答:解:(1)47+256+53
=(47+53)+256,
=100+256,
=356;
(2)368-152-48
=368-(152+48),
=368-200,
=168;
(3)25×17×4
=25×4×17,
=100×17,
=1700;
(4)2700÷25÷4
=2700÷(25×4),
=2700÷100,
=27;
(5)125×88
=125×8×11,
=1000×11,
=11000;
(6)99×41+41
=(99+1)×41,
=100×41,
=4100;
(7)13×75+13×25
=(75+25)×13,
=100×13,
=1300;
(8)125×72
=125×8×9,
=1000×9,
=9000;
(9)25×(4+8),
=25×4+25×8,
=100+200,
=300.
=(47+53)+256,
=100+256,
=356;
(2)368-152-48
=368-(152+48),
=368-200,
=168;
(3)25×17×4
=25×4×17,
=100×17,
=1700;
(4)2700÷25÷4
=2700÷(25×4),
=2700÷100,
=27;
(5)125×88
=125×8×11,
=1000×11,
=11000;
(6)99×41+41
=(99+1)×41,
=100×41,
=4100;
(7)13×75+13×25
=(75+25)×13,
=100×13,
=1300;
(8)125×72
=125×8×9,
=1000×9,
=9000;
(9)25×(4+8),
=25×4+25×8,
=100+200,
=300.
点评:完成本题要注意分析式中数据的特点及内在联系,然后选择合适的方法进行计算.
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