题目内容
解方程. 5.6+χ=10 |
5χ=1.3 |
χ÷0.08=2.5 | χ-0.42=6.9 |
分析:(1)依据等式的性质,方程两边同时减5.6求解,
(2)依据等式的性质,方程两边同时除以5求解,
(3)依据等式的性质,方程两边同时乘0.08求解,
(4)依据等式的性质,方程两边同时加0.42求解.
(2)依据等式的性质,方程两边同时除以5求解,
(3)依据等式的性质,方程两边同时乘0.08求解,
(4)依据等式的性质,方程两边同时加0.42求解.
解答:解:(1)5.6+x=10
5.6+x-5.6=10-5.6
x=4.4;
(2)5x=1.3
5x÷5=1.3÷5
x=0.26;
(3)x÷0.08=2.5
x÷0.08×0.08=2.5×0.08
x=0.2;
(4)x-0.42=6.9
x-0.42+0.42=6.9+0.42
x=7.32.
5.6+x-5.6=10-5.6
x=4.4;
(2)5x=1.3
5x÷5=1.3÷5
x=0.26;
(3)x÷0.08=2.5
x÷0.08×0.08=2.5×0.08
x=0.2;
(4)x-0.42=6.9
x-0.42+0.42=6.9+0.42
x=7.32.
点评:本题考查知识点:依据等式的性质解方程,解方程时注意对齐等号.
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