题目内容
|
|
|
| ||||||||||||||||||
|
x:
|
x:
|
x:
|
分析:解比例,先根据比例的基本性质,把比例式转化成方程式,(如:
=
,2x=8×9.)然后再根据等式的基本性质,逐步求解即可.
2 |
8 |
9 |
x |
解答:解:
=
,
2x=8×9,
x=36;
:
=
:x,
x=
×
,
x=
×
×2,
x=
;
:20=
:x,
x=20×
,
x=20×
×
,
x=5
;
=
,
0.25x=1.25×1.6,
x=
,
x=8;
:x=5:16,
5x=16×
,
x=8×
,
x=1
;
x:
=18:
,
x=18×
,
x=16×4,
x=64;
x:
=
:
,
x=
×
,
x=
×
,
x=
;
x:
=
:
,
x=
×
,
x=
×4,
x=1
.
2 |
8 |
9 |
x |
2x=8×9,
x=36;
1 |
2 |
1 |
5 |
1 |
4 |
1 |
2 |
1 |
5 |
1 |
4 |
x=
1 |
5 |
1 |
4 |
x=
1 |
10 |
3 |
4 |
1 |
5 |
3 |
4 |
1 |
5 |
x=20×
1 |
5 |
4 |
3 |
x=5
1 |
3 |
1.25 |
0.25 |
x |
1.6 |
0.25x=1.25×1.6,
x=
1.25×1.6 |
0.25 |
x=8;
1 |
2 |
5x=16×
1 |
2 |
x=8×
1 |
5 |
x=1
3 |
5 |
x:
8 |
9 |
1 |
4 |
1 |
4 |
8 |
9 |
x=16×4,
x=64;
x:
1 |
2 |
4 |
5 |
3 |
4 |
3 |
4 |
1 |
2 |
4 |
5 |
x=
2 |
5 |
4 |
3 |
x=
8 |
15 |
x:
2 |
5 |
2 |
3 |
1 |
4 |
1 |
4 |
2 |
5 |
2 |
3 |
x=
4 |
15 |
x=1
1 |
15 |
点评:解答此题的关键是根据比例和等式的基本性质求解.
练习册系列答案
相关题目