题目内容
解方程.
![]() ![]() | x:15=2. |
解;(1)
x=
,
x×
=
,
x=
;
(2)x:15=2,
x×
×15=2×15,
x=30;
分析:(1)方程的两边同时乘以
即可求得未知数的值.(2)先把比号边长变成除号,进一步把除法转换成乘法,然后再运用等式的性质进行计算即可.
点评:把除号变成乘号,然后运用等式的性质进行解答.
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x=

(2)x:15=2,
x×

x=30;
分析:(1)方程的两边同时乘以

点评:把除号变成乘号,然后运用等式的性质进行解答.

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