题目内容
(2007?慈溪市)(1)(3a-4)-3×(a-4)=
(2)已知a-12=c,那么(a+c+12)÷a=
8
8
(2)已知a-12=c,那么(a+c+12)÷a=
2
2
.分析:(1)根据乘法分配律计算,再去括号,然后再根据加法交换律和结合律计算即可;
(2)用a表示c,代入(a+c+12)÷a即可求解.
(2)用a表示c,代入(a+c+12)÷a即可求解.
解答:解:(1)(3a-4)-3×(a-4)
=3a-4-3a+12
=(3a-3a)+(12-4)
=0+8
=8;
(2)a-12=c,即c=a-12,
则(a+c+12)÷a
=(a+a-12+12)÷a
=2a÷a
=2.
=3a-4-3a+12
=(3a-3a)+(12-4)
=0+8
=8;
(2)a-12=c,即c=a-12,
则(a+c+12)÷a
=(a+a-12+12)÷a
=2a÷a
=2.
点评:本题考查了含字母式子的求值,注意灵活运用运算律,(2)中关键是用a表示c,代入求解.
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