题目内容

(1)
1
2
×3+5×
1
2
         
(2)3×(
1
15
+
1
12
)-
2
5
         
(3)
1
3
+3-(
1
4
+
1
12
(4)
3
4
×
5
7
×
4
3
-
1
2
      
(5)
15
16
+(
7
16
-
1
4
)÷
1
2
         
(6)
2
3
+(
4
7
+
1
2
)×
7
25
(7)
1
4
+2X=
1
2
        
(8)5X-
5
6
=
5
12
         
(9)
2
3
X-
1
5
X=1
(10)X+
7
9
X=
4
3
分析:(1)根据乘法分配律进行简算;
(2)根据乘法分配律简算简算;
(3)先算小括号里面的加法,再算根据加法交换律进行简算;
(4)根据乘法交换律进行简算;
(5)先算减法,再算除法,最后算加法;
(6)先算小括号里面的加法,再算乘法,最后算括号外面的加法;
(7)、(8)、(9)、(10)根据等式的性质进行解答.
解答:解:
(1)
1
2
×3+5×
1
2

=
1
2
×(3+5),
=
1
2
×8,
=4;

(2)3×(
1
15
+
1
12
)-
2
5

=3×
1
15
+3×
1
12
-
2
5

=
1
5
+
1
4
-
2
5

=
9
20
-
2
5

=
1
20


(3)
1
3
+3-(
1
4
+
1
12
),
=
1
3
+3-
1
3

=
1
3
-
1
3
+3,
=3;

(4)
3
4
×
5
7
×
4
3
-
1
2

=
3
4
×
4
3
×
5
7
-
1
2

=
5
7
-
1
2

=
3
14


(5)
15
16
+(
7
16
-
1
4
)÷
1
2

=
15
16
+
3
16
÷
1
2

=
15
16
+
3
8

=
21
16


(6)
2
3
+(
4
7
+
1
2
)×
7
25

=
2
3
+
15
14
×
7
25

=
2
3
+
3
10

=
29
30


(7)
1
4
+2X=
1
2

 
1
4
+2X-
1
4
=
1
2
-
1
4

       2X=
1
4

    2X÷2=
1
4
÷2,
        X=
1
8


(8)5X-
5
6
=
5
12

  5X-
5
6
+
5
6
=
5
12
+
5
6

       5X=
5
4

     5X÷=
5
4
÷5,
        X=
1
4


(9)
2
3
X-
1
5
X=1,
      
7
15
X=1,
  
7
15
7
15
=1÷
7
15

          X=
15
7



(10)X+
7
9
X=
4
3

      
16
9
X=
4
3

  
16
9
16
9
=
4
3
÷
16
9

          X=
3
4
点评:考查了运算定律与简便运算,四则混合运算以及解方程.注意运算顺序和运算法则,灵活运用所学的运算定律简便计算;解方程根据等式的性质进行解答.
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