题目内容
解方程.
x-3.6=1.4 | 4x=15 | x+0.42=4.2 | x÷1.4=0.5. |
分析:(1)等式两边同时加上3.6;
(2)等式两边同时除以4;
(3)等式两边同时减去0.42;
(4)等式两边同时乘1.4;即可得解.
(2)等式两边同时除以4;
(3)等式两边同时减去0.42;
(4)等式两边同时乘1.4;即可得解.
解答:解:(1)x-3.6=1.4,
x-3.6+3.6=1.4+3.6,
x=5;
(2)4x=15,
4x÷4=15÷4,
x=3.75;
(3)x+0.42=4.2,
x+0.42-0.42=4.2-0.42,
x=3.78;
(4)x÷1.4=0.5,
x÷1.4×1.4=0.5×1.4,
x=0.7.
x-3.6+3.6=1.4+3.6,
x=5;
(2)4x=15,
4x÷4=15÷4,
x=3.75;
(3)x+0.42=4.2,
x+0.42-0.42=4.2-0.42,
x=3.78;
(4)x÷1.4=0.5,
x÷1.4×1.4=0.5×1.4,
x=0.7.
点评:此题考查了解方程,利用等式的基本性质来解决问题.
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