题目内容
合理灵活地进行计算.
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4×[(
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分析:(1)运用除法性质解答,
(2)按照先算括号里面的减法,再算括号外面的乘法顺序计算即可解答,
(3)按照先算小括号里面的,再算中括号里面的,最后算括号外面的顺序计算即可解答,
(4)运用乘法分配律解答.
(2)按照先算括号里面的减法,再算括号外面的乘法顺序计算即可解答,
(3)按照先算小括号里面的,再算中括号里面的,最后算括号外面的顺序计算即可解答,
(4)运用乘法分配律解答.
解答:解:(1)
÷
÷
=
÷(
×
)
=
÷
=1
;
(2)
×(
-
)
=
×
=
;
(3)4×[(
+
)÷6]
=4×[
÷6]
=4×
=1;
(4)
×
+
÷15
=(
+
)×
=1×
=
.
5 |
8 |
20 |
21 |
7 |
12 |
=
5 |
8 |
20 |
21 |
7 |
12 |
=
5 |
8 |
5 |
9 |
=1
1 |
8 |
(2)
3 |
4 |
17 |
18 |
5 |
9 |
=
3 |
4 |
7 |
18 |
=
7 |
24 |
(3)4×[(
5 |
6 |
2 |
3 |
=4×[
3 |
2 |
=4×
1 |
4 |
=1;
(4)
3 |
7 |
1 |
15 |
4 |
7 |
=(
3 |
7 |
4 |
7 |
1 |
15 |
=1×
1 |
15 |
=
1 |
15 |
点评:(1)依据四则运算计算方法正确进行计算,(2)运用简便方法解决问题,是本题考查知识点.

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