题目内容
解方程.
x-12%x=2.816 |
|
分析:(1)原式变为(1-12%)x=2.816,即0.88x=2.816,根据等式的性质,两边同除以0.88即可;
(2)原式变为
-
x=
,根据等式的性质,两边同加上
x,得
x=
,两边同乘2即可.
(2)原式变为
1 |
5 |
1 |
2 |
1 |
20 |
1 |
2 |
1 |
2 |
3 |
20 |
解答:解:(1)x-12%x=2.816,
(1-12%)x=2.816,
0.88x=2.816,
0.88x÷0.88=2.816÷0.88,
x=3.2;
(2)
×
-
x=
,
-
x=
,
-
x+
x=
+
x,
+
x=
,
+
x-
=
-
,
x=
,
x×2=
×2,
x=
.
(1-12%)x=2.816,
0.88x=2.816,
0.88x÷0.88=2.816÷0.88,
x=3.2;
(2)
4 |
5 |
1 |
4 |
1 |
2 |
1 |
20 |
1 |
5 |
1 |
2 |
1 |
20 |
1 |
5 |
1 |
2 |
1 |
2 |
1 |
20 |
1 |
2 |
1 |
20 |
1 |
2 |
1 |
5 |
1 |
20 |
1 |
2 |
1 |
20 |
1 |
5 |
1 |
20 |
1 |
2 |
3 |
20 |
1 |
2 |
3 |
20 |
x=
3 |
10 |
点评:在解方程时应根据等式的性质,即等式两边同加上、同减去、同乘上或同除以某一个数(0除外),等式的两边仍相等,同时注意“=”上下要对齐.
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