题目内容
递等式计算.
(1)234×98÷49
(2)36×36+36×64
(3)(2012-159)÷17
(4)398-173-27+112.
(1)234×98÷49
(2)36×36+36×64
(3)(2012-159)÷17
(4)398-173-27+112.
分析:(1)运用乘法结合律简算;
(2)运用乘法分配律简算;
(3)先算小括号里面的减法,再算括号外的除法;
(4)根据加法结合律以及减法的性质简算.
(2)运用乘法分配律简算;
(3)先算小括号里面的减法,再算括号外的除法;
(4)根据加法结合律以及减法的性质简算.
解答:解:(1)234×98÷49,
=234×(98÷49),
=234×2,
=468;
(2)36×36+36×64,
=36×(36+64),
=36×100,
=3600;
(3)(2012-159)÷17,
=1853÷17,
=109;
(4)398-173-27+112,
=(398+112)-(173+27),
=500-200,
=300.
=234×(98÷49),
=234×2,
=468;
(2)36×36+36×64,
=36×(36+64),
=36×100,
=3600;
(3)(2012-159)÷17,
=1853÷17,
=109;
(4)398-173-27+112,
=(398+112)-(173+27),
=500-200,
=300.
点评:此题是考查四则混合运算,要仔细观察算式的特点,灵活运用一些定律进行简便计算.
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