题目内容
9.8×65.2×1.25-12.5×0.652×18
8(x-2)=2(x+7)
×7-12×
(22+6):7=(A-6):9
60%:90%=A:
规定a◇b=(a+b)÷b,已知m◇(4◇2)=1.2,求m的值.
8(x-2)=2(x+7)
6 |
11 |
3 |
11 |
(22+6):7=(A-6):9
60%:90%=A:
1 |
12 |
规定a◇b=(a+b)÷b,已知m◇(4◇2)=1.2,求m的值.
分析:(1)根据数字特点,把原式变为9.8×6.52×12.5-12.5×6.52×1.8,运用乘法分配律的逆运算简算;
(2)根据等式的性质,两边同除以2,得4(x-2)=x+7,即4x-8=x+7,两边同加上8,得4x=x+15,两边同减去x,得3x=15,两边再同除以3即可;
(3)先把原式变为
×7-6×
,运用乘法分配律的逆运算简算;
(4)先计算22+6=28,再根据比例的基本性质改写成7×(A-6)=28×9,即7A-42=252,根据等式的性质,两边同加上42,再同除以7即可;
(5)先根据比例的基本性质改写成0.9A=0.6×
,再根据等式的性质,两边同除以0.9即可;
(6)根据定义,先求出4◇2的值,再把m和这个值按规定运算,转化为一般方程,最后求出m的值.
(2)根据等式的性质,两边同除以2,得4(x-2)=x+7,即4x-8=x+7,两边同加上8,得4x=x+15,两边同减去x,得3x=15,两边再同除以3即可;
(3)先把原式变为
6 |
11 |
6 |
11 |
(4)先计算22+6=28,再根据比例的基本性质改写成7×(A-6)=28×9,即7A-42=252,根据等式的性质,两边同加上42,再同除以7即可;
(5)先根据比例的基本性质改写成0.9A=0.6×
1 |
12 |
(6)根据定义,先求出4◇2的值,再把m和这个值按规定运算,转化为一般方程,最后求出m的值.
解答:解:(1)9.8×65.2×1.25-12.5×0.652×18,
=9.8×6.52×12.5-12.5×6.52×1.8,
=6.52×12.5×(9.8-1.8),
=6.52×12.5×8,
=6.52×100,
=652;
(2)8(x-2)=2(x+7),
8(x-2)÷2=2(x+7)÷2,
4(x-2)=x+7,
4x-8=x+7,
4x-8+8=x+7+8,
4x=x+15,
4x-x=x+15-x,
3x=15,
3x÷3=15÷3,
x=5;
(3)
×7-12×
,
=
×7-6×
,
=(7-6)×
,
=
;
(4)(22+6):7=(A-6):9,
28:7=(A-6):9,
7×(A-6)=28×9,
7A-42=252,
7A-42+42=252+42,
7A=294,
7A÷7=294÷7,
A=42;
(5)60%:90%=A:
,
0.9A=0.6×
,
09A÷0.9=
÷0.9,
A=
;
(6)4◇2=(4+2)÷2=6÷2=3;
m◇3=(m+3)÷3;
因此(m+3)÷3=1.2,
(m+3)÷3×3=1.2×3,
m+3=3.6,
m+3-3=3.6-3,
m=0.6.
答:m的值是0.6.
=9.8×6.52×12.5-12.5×6.52×1.8,
=6.52×12.5×(9.8-1.8),
=6.52×12.5×8,
=6.52×100,
=652;
(2)8(x-2)=2(x+7),
8(x-2)÷2=2(x+7)÷2,
4(x-2)=x+7,
4x-8=x+7,
4x-8+8=x+7+8,
4x=x+15,
4x-x=x+15-x,
3x=15,
3x÷3=15÷3,
x=5;
(3)
6 |
11 |
3 |
11 |
=
6 |
11 |
6 |
11 |
=(7-6)×
6 |
11 |
=
6 |
11 |
(4)(22+6):7=(A-6):9,
28:7=(A-6):9,
7×(A-6)=28×9,
7A-42=252,
7A-42+42=252+42,
7A=294,
7A÷7=294÷7,
A=42;
(5)60%:90%=A:
1 |
12 |
0.9A=0.6×
1 |
12 |
09A÷0.9=
1 |
20 |
A=
1 |
18 |
(6)4◇2=(4+2)÷2=6÷2=3;
m◇3=(m+3)÷3;
因此(m+3)÷3=1.2,
(m+3)÷3×3=1.2×3,
m+3=3.6,
m+3-3=3.6-3,
m=0.6.
答:m的值是0.6.
点评:此题考查了小数的四则混合运算、解方程以及定义新运算,根据不同题目的特点,选择合适的方法解答.
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