题目内容
(2011?江阴市)递等式计算
43×99+43
3÷
-
×
(27+
)÷9
÷[(
+
)÷
].
43×99+43
3÷
1 |
2 |
1 |
4 |
3 |
10 |
(27+
18 |
19 |
3 |
5 |
1 |
5 |
1 |
3 |
2 |
9 |
分析:算式(1)、(3)可据分配律进行简算;算式(2)、(4)据四则混合运算法则计算即可.
解答:解:(1)43×99+43
=43×(99+1),
=42×100,
=4200;
(2)3÷
-
×
=3×2-
,
=6-
,
=5
;
(3)(27+
)÷9
=27÷9+
×
,
=3+
,
=3
;
(4)
÷[(
+
)÷
]
=
÷[
÷
],
=
÷
,
=
.
=43×(99+1),
=42×100,
=4200;
(2)3÷
1 |
2 |
1 |
4 |
3 |
10 |
=3×2-
3 |
40 |
=6-
3 |
40 |
=5
37 |
40 |
(3)(27+
19 |
19 |
=27÷9+
18 |
19 |
1 |
9 |
=3+
2 |
19 |
=3
2 |
19 |
(4)
3 |
5 |
1 |
5 |
1 |
3 |
2 |
9 |
=
3 |
5 |
8 |
15 |
2 |
9 |
=
3 |
5 |
12 |
5 |
=
1 |
4 |
点评:完成本题要认真分析式中数据,能简算的要简算.
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