题目内容

11.在□里填上适当的分数
1÷($\frac{4}{5}$×□-$\frac{1}{5}$ )=3.

分析 把□看作未知数x,根据等式的性质解方程即可即可.

解答 解:把□看作未知数x,
             1÷($\frac{4}{5}$×x-$\frac{1}{5}$)=3
1÷($\frac{4}{5}$×x-$\frac{1}{5}$)×($\frac{4}{5}$×x-$\frac{1}{5}$)=3×($\frac{4}{5}$×x-$\frac{1}{5}$)
             3×($\frac{4}{5}$×x-$\frac{1}{5}$)=1
          3×($\frac{4}{5}$×x-$\frac{1}{5}$)÷3=1÷3
                    $\frac{4}{5}$×x-$\frac{1}{5}$=$\frac{1}{3}$
                 $\frac{4}{5}$×x-$\frac{1}{5}$+$\frac{1}{5}$=$\frac{1}{3}$+$\frac{1}{5}$
                      $\frac{4}{5}$×x=$\frac{8}{15}$
                   $\frac{4}{5}$×x×$\frac{5}{4}$=$\frac{8}{15}$×$\frac{5}{4}$
                          x=$\frac{2}{3}$
即□=$\frac{2}{3}$.

点评 此题把□看作未知数,依据等式的性质进行求解,注意等号对齐.

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