题目内容
计算. ①24×(
|
②45×
|
③[1-(
| ||||||||||||||||||
④
|
⑤
|
⑥
|
分析:(1)根据乘法分配律进行计算,
(2)先变形,再根据乘法分配律进行计算,
(3)先算括号里面的,再算中括号里面的,最后算除法,
(4)根据加法交换律及减法的性质进行计算,
(5)先把除法化成乘法,再根据乘法的计算方法进行计算,
(6)根据乘法分配律进行计算.
(2)先变形,再根据乘法分配律进行计算,
(3)先算括号里面的,再算中括号里面的,最后算除法,
(4)根据加法交换律及减法的性质进行计算,
(5)先把除法化成乘法,再根据乘法的计算方法进行计算,
(6)根据乘法分配律进行计算.
解答:解:(1)24×(
-
),
=24×
-24×
,
=39-6,
=33;
(2)45×
+56×37.5%-0.375,
=45×0.375+56×0.375-0.375,
=0.375×(45+56-1),
=0.375×100,
=37.5.
(3)[1-(
+
)]÷
,
=[1-
]÷
,
=
÷
,
=
;
(4)
-
+
-
,
=
-
-
+
,
=
-(
+
)+
,
=
+
-1,
=2-1,
=1;
(5)
×8÷
×5,
=
×8×
×5,
=25;
(6)
×(
×17+
),
=
×[(
×(17+1)],
=
×[
×18],
=
×9,
=
.
13 |
8 |
3 |
12 |
=24×
13 |
8 |
3 |
12 |
=39-6,
=33;
(2)45×
3 |
8 |
=45×0.375+56×0.375-0.375,
=0.375×(45+56-1),
=0.375×100,
=37.5.
(3)[1-(
1 |
4 |
3 |
8 |
3 |
4 |
=[1-
5 |
8 |
3 |
4 |
=
3 |
8 |
3 |
4 |
=
1 |
2 |
(4)
13 |
19 |
3 |
13 |
25 |
19 |
10 |
13 |
=
13 |
19 |
3 |
13 |
10 |
13 |
25 |
19 |
=
13 |
19 |
3 |
13 |
10 |
13 |
25 |
19 |
=
13 |
19 |
25 |
19 |
=2-1,
=1;
(5)
3 |
8 |
3 |
5 |
=
3 |
8 |
5 |
3 |
=25;
(6)
13 |
18 |
9 |
18 |
9 |
18 |
=
13 |
18 |
9 |
18 |
=
13 |
18 |
9 |
18 |
=
13 |
18 |
=
13 |
2 |
点评:本题主要考查了学生的计算能力,以及在计算中灵活运用简便算法的能力.
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