题目内容
(2005?宜兴市)用递等式计算.
(1)168.1÷(4.3×2-0.4)
(2)
×[
-(
-
)].
(1)168.1÷(4.3×2-0.4)
(2)
4 |
9 |
3 |
4 |
7 |
16 |
1 |
4 |
分析:按照四则混合运算的运算顺序和计算法则进行计算.
解答:解:(1)168.1÷(4.3×2-0.4),
=168.1÷(8.6-0.4),
=168.1÷8.2,
=20.5;
(2)
×[
-(
-
)],
=
×[
-
],
=
×
,
=
.
=168.1÷(8.6-0.4),
=168.1÷8.2,
=20.5;
(2)
4 |
9 |
3 |
4 |
7 |
16 |
1 |
4 |
=
4 |
9 |
3 |
4 |
3 |
16 |
=
4 |
9 |
9 |
16 |
=
1 |
4 |
点评:此题综合考查了小数和分数的四则混合运算,要细心按顺序和计算法则进行计算.
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