题目内容
(2010?武陵区)用递等式计算下面各题,能简算的要简算
×0.25+
×
(
+
-
)×12
3
×8-3
×6+3×3.75
863+47.95÷0.35-529.
5 |
6 |
1 |
4 |
1 |
6 |
(
3 |
4 |
11 |
6 |
13 |
24 |
3
3 |
4 |
3 |
4 |
863+47.95÷0.35-529.
分析:(1)(3)可先将式中的小数化为分数后,再根据乘法分配律计算;
(2)根据根据乘法分配律计算即可;
(4)根据四则混合运算的运算顺序计算即可,先算除法,再算加法和减法.
(2)根据根据乘法分配律计算即可;
(4)根据四则混合运算的运算顺序计算即可,先算除法,再算加法和减法.
解答:解:(1)
×0.25+
×
=
×
+
×
,
=(
+
)×
,
=1×
,
=
;
(2)(
+
-
)×12,
=
×12+
×12-
×12,
=9+22-6
,
=24
;
(3)3
×8-3
×6+3×3.75
=3
×8-3
×6+3×3
,
=(8-6+3)×3
,
=5×3
,
=18
;
863+47.95÷0.35-529
=863+137-529,
=1000-529,
=471.
5 |
6 |
1 |
4 |
1 |
6 |
=
5 |
6 |
1 |
4 |
1 |
4 |
1 |
6 |
=(
5 |
6 |
1 |
6 |
1 |
4 |
=1×
1 |
4 |
=
1 |
4 |
(2)(
3 |
4 |
11 |
6 |
13 |
24 |
=
3 |
4 |
11 |
6 |
13 |
24 |
=9+22-6
1 |
2 |
=24
1 |
2 |
(3)3
3 |
4 |
3 |
4 |
=3
3 |
4 |
3 |
4 |
3 |
4 |
=(8-6+3)×3
3 |
4 |
=5×3
3 |
4 |
=18
3 |
4 |
863+47.95÷0.35-529
=863+137-529,
=1000-529,
=471.
点评:当算式中同时含有分数与小数时,要根据式中数据的特点灵活将它们互化后再进行计算.
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