题目内容
数学门诊.(把不对的改正过来)
(1)1.7×0.31+0.69×1.7
=1.7×(0.31+0.69)×1.7
=1.7×1×1.7
=2.89
改正:
(2)0.25×12
=0.25×(4×3)
=0.25×4+0.25×3
=1+0.75
=1.75
改正:
(3)3.5×103
=3.5×100+3
=350+3
=353
改正:
(1)1.7×0.31+0.69×1.7
=1.7×(0.31+0.69)×1.7
=1.7×1×1.7
=2.89
×
×
改正:
(2)0.25×12
=0.25×(4×3)
=0.25×4+0.25×3
=1+0.75
=1.75
×
×
改正:
(3)3.5×103
=3.5×100+3
=350+3
=353
×
×
改正:
分析:(1)运用乘法分配律时,用1.7分别与0.31和0.69相乘即可,原式多乘了一个1.7,故本题错误;
(2)把12看作4×3,即0.25×(4×3),运用乘法结合律简算,括号内是乘法不是加法,因此不能写成0.25×4+0.25×3,故本题错误;
(3)把103看作100+3,原式变为3.5×(100+3),运用乘法结合律简算时,用3.5分别与100和3相乘,再相加.
(2)把12看作4×3,即0.25×(4×3),运用乘法结合律简算,括号内是乘法不是加法,因此不能写成0.25×4+0.25×3,故本题错误;
(3)把103看作100+3,原式变为3.5×(100+3),运用乘法结合律简算时,用3.5分别与100和3相乘,再相加.
解答:解:(1)1.7×0.31+0.69×1.7
=1.7×(0.31+0.69)×1.7
=1.7×1×1.7
=2.89×
改正:1.7×0.31+0.69×1.7
=1.7×(0.31+0.69)
=1.7×1,
=1.7;
(2)0.25×12
=0.25×(4×3)
=0.25×4+0.25×3
=1+0.75
=1.75×
改正:0.25×12
=0.25×(4×3)
=(0.25×4)×3
=1×3,
=3;
(3)3.5×103
=3.5×100+3
=350+3
=353×
改正:3.5×103
=3.5×(100+3)
=3.5×100+3.5×3
=3500+10.5,
=3510.5.
故答案为:×,×,×.
=1.7×(0.31+0.69)×1.7
=1.7×1×1.7
=2.89×
改正:1.7×0.31+0.69×1.7
=1.7×(0.31+0.69)
=1.7×1,
=1.7;
(2)0.25×12
=0.25×(4×3)
=0.25×4+0.25×3
=1+0.75
=1.75×
改正:0.25×12
=0.25×(4×3)
=(0.25×4)×3
=1×3,
=3;
(3)3.5×103
=3.5×100+3
=350+3
=353×
改正:3.5×103
=3.5×(100+3)
=3.5×100+3.5×3
=3500+10.5,
=3510.5.
故答案为:×,×,×.
点评:此题考查了学生对乘法分配律的正确掌握与运用.
练习册系列答案
相关题目