题目内容
19.选择你认为最合理的方法计算下列各题:3780÷54+1620÷54 $\frac{6}{7}$-$\frac{6}{7}$×( $\frac{2}{3}$+$\frac{1}{9}$) 23-$\frac{12}{17}$-$\frac{5}{17}$
$\frac{11}{16}$×40-$\frac{9}{16}$÷$\frac{1}{40}$ 10.2-(1.25+2.5)÷1.5 1$\frac{1}{8}$÷($\frac{1}{4}$+2.5×$\frac{4}{5}$)
分析 (1)先算除法,再算加法;
(2)先算小括号里的加法,再运用乘法的分配律进行简算;
(3)运用减法的性质进行简算;
(4)把除以$\frac{1}{40}$化成乘以40,再运用乘法的分配律进行简算;
(5)先算小括号里的加法,再算括号外的除法,最后算括号外的减法;
(6)先算小括号里的乘法,再算小括号里的加法,最后算括号外的除法.
解答 解:(1)3780÷54+1620÷54
=70+30
=100;
(2)$\frac{6}{7}$-$\frac{6}{7}$×( $\frac{2}{3}$+$\frac{1}{9}$)
=$\frac{6}{7}$-$\frac{6}{7}$×$\frac{7}{9}$
=$\frac{6}{7}$×(1-$\frac{7}{9}$)
=$\frac{6}{7}$×$\frac{2}{9}$
=$\frac{4}{21}$;
(3)23-$\frac{12}{17}$-$\frac{5}{17}$
=23-($\frac{12}{17}$+$\frac{5}{17}$)
=23-1
=22;
(4)$\frac{11}{16}$×40-$\frac{9}{16}$÷$\frac{1}{40}$
=$\frac{11}{16}$×40-$\frac{9}{16}$×40
=($\frac{11}{16}$-$\frac{9}{16}$)×40
=$\frac{1}{8}×40$
=5;
(5)10.2-(1.25+2.5)÷1.5
=10.2-3.75÷1.5
=10.2-2.5
=7.7;
(6)1$\frac{1}{8}$÷($\frac{1}{4}$+2.5×$\frac{4}{5}$)
=1$\frac{1}{8}$÷($\frac{1}{4}$+2)
=1$\frac{1}{8}$÷2$\frac{1}{4}$
=0.5.
点评 仔细观察题目中数字构成的特点和规律,运用运算定律或运算技巧,进行简便计算.