题目内容
运用简便方法计算.
×
+
×
+
×
(7
+5
)÷(
+
)
132÷132
.
5 |
6 |
1 |
13 |
5 |
9 |
2 |
13 |
5 |
18 |
6 |
13 |
(7
3 |
5 |
3 |
7 |
2 |
5 |
2 |
7 |
132÷132
132 |
133 |
考点:运算定律与简便运算
专题:运算定律及简算
分析:(1)通过数字转化,运用乘法分配律简算.
(2)通过数字转化,运用除法的运算性质简算.
(3)把带分数化成假分数,分子不必算出来,通过约分简算即可.
(2)通过数字转化,运用除法的运算性质简算.
(3)把带分数化成假分数,分子不必算出来,通过约分简算即可.
解答:
解:(1)
×
+
×
+
×
=
×
+
×
+
×
=(
+
+
)×
=
×
=
(2)(7
+5
)÷(
+
)
=[7+5+(
+
)×3]÷(
+
)×2
=[12+(
+
)×3]÷[(
+
)×2]
=12÷[(
+
)×2]+[(
+
)×3]÷[(
+
)×2]
=12÷
+
=
+
=19
(3)132÷132
=132÷
=132÷
=132×
=
5 |
6 |
1 |
13 |
5 |
9 |
2 |
13 |
5 |
18 |
6 |
13 |
=
5 |
6 |
1 |
13 |
10 |
9 |
1 |
13 |
5 |
3 |
1 |
13 |
=(
5 |
6 |
10 |
9 |
5 |
3 |
1 |
13 |
=
65 |
18 |
1 |
13 |
=
5 |
18 |
(2)(7
3 |
5 |
3 |
7 |
2 |
5 |
2 |
7 |
=[7+5+(
1 |
5 |
1 |
7 |
1 |
5 |
1 |
7 |
=[12+(
1 |
5 |
1 |
7 |
1 |
5 |
1 |
7 |
=12÷[(
1 |
5 |
1 |
7 |
1 |
5 |
1 |
7 |
1 |
5 |
1 |
7 |
=12÷
24 |
35 |
3 |
2 |
=
35 |
2 |
3 |
2 |
=19
(3)132÷132
132 |
133 |
=132÷
133×132+132 |
133 |
=132÷
132×134 |
133 |
=132×
133 |
132×134 |
=
133 |
134 |
点评:完成本题要注意分析式中数据,运用合适的简便方法计算.
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